In maize (corn) plants, a dominant allele I inhibits kernel color, while the recessive allele i permits color when homozygous. At a different locus, the dominant allele P causes purple kernel color, while the homozygous recessive genotype pp causes red kernels. If plants heterozygous at both loci are crossed, what will be the phenotypic ratio of the offspring?
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- In peas, the allele Le produces tall plants and the allele le produces dwarf plants. The Le allele is dominant to le. If a tall plant is crossed with a dwarf, the offspring are distributed about equally between tall and dwarf plants. What are the genotypes of the parents?The dominant C allele of a gene that controls color in corn produces kernels with color; plants homozygous for a recessive c allele of this gene have colorless or white kernels. What kinds of gametes, and in what proportions, would be produced by the plants in the following crosses? What seed color, and in what proportions, would be expected in the offspring of the crosses? a. CCCc b. Cccc c. CcCcIn sweet pea plants, an allele for purple flowers. (P) is dominanl when paired with a recessive allele for red flowers (p). An allele for Jang pollen grains (L) is dominant when paired with a recessive allele for round pollen grains (L). Bateson and Punnett crossed a plant having purple flowers and long pollen grains with one having white flowers and round pollen grains. All F1 offspring have purple flowers and long pollen grains. Among the F2 generation, the researchers observed the following phenotypes: 296 purple flowers/long pollen grains 19 purple /lower/ round pollen grains 27 red flowers/long pollen grains 85 red flowers/round pollen grains What is the best explanation for these results?
- Several alleles affect traits of roses, such as plant form and bud shape. Alleles of one gene govern whether a plant will be a climber (dominant) or shrubby (recessive). All F1 offspring from a cross between a true-breeding climber and a shrubby plant are climbers. If an F1 plant is crossed with a shrubby plant, about 50 percent of the offspring will be shrubby; 50 percent will be climbers. Using symbols A and a for the dominant and recessive alleles, make a Punnett- square diagram of the expected genotypes and phenotypes the cross between the F1 offspring and the shrubby plant.6. In corn plants, a dominant allele I inhibits kernel color, while the recessive allele i permits color when homozygous. At a different locus, the dominant gene P causes purple kernel color while the homozygous recessive pp causes red kernels. If a plant that is heterozygous at both loci is crossed with a plant that has red kernels, what will be the phenotypic ratio of the offsprings?1. Alleles of the gene that determines seed coat patternsin lentils can be organized in a dominance series:marbled > spotted = dotted (codominant alleles) >clear. A lentil plant homozygous for the marbled seedcoat pattern allele was crossed to one homozygous forthe spotted pattern allele. In another cross, a homozygous dotted lentil plant was crossed to one homozygous for clear. An F1 plant from the first cross wasthen mated to an F1 plant from the second cross.a. What phenotypes in what proportions are expectedfrom this mating between the two F1 types?b. What are the expected phenotypes of the F1 plantsfrom the two original parental crosses?
- 4. Albinism is lethal in plants, but many plants produce albino offspring. If albino plants C always die before reproducing, how does albinism persist? Migh ne 5. Mendel crossed pea plants producing round seeds with those producing wrinkled seeds. Of 7,324 F2 seeds, 5,464 were round, and 1,860 were wrinkled. Using the symbols W and w for the alleles, (a) symbolize the original P₁ cross; Slover don pet (b) determine the parental gametes; 69 (c) show the F₁ offspring; (d) show a cross between two F₁ plants; dong berbella" 10. Jogolų ar preu 39 woy Your Mirb & ever ascohes berloste di ritod 8 201 artW.20 meylo evit bins tight pdchse sent sitt 10 euogysomod Ceadolise borbeis blirib o svad Jism adoles Parl (e) symbolize the F₁ gametes; and, odb seit (f) summarize the expected F2 results for phenotypes, genotypes and phenotype ratios. mun 100 3161 16 gr nation ritiw nam A (6) His neblinks Sylimstedt phow yd showenis uby sloy 6 or be 160 (0) endonce 100 to eno elouosis na (b) wari hot…10. You are testing Drosophila for the following recessive genes: "spinless" without bristles on the wings; "claret" dark brown eyes; and "hairless" without thoracic bristles. You do a test cross with a heterozygous female for all three genes, and you get the following progeny: spineless 82wild 380claret, spinless 130claret 18claret, hairless 80hairless, claret, spinless 323hairless 140hairless, spinless 12 The correct distance between sp - cl genes is: a. 0.25 umb. 0.36 umc. 41 umd. 25 ume. 16 um 11. You are testing Drosophila for the following recessive genes: "spinless" without bristles on the wings; "claret" dark brown eyes; and "hairless" without thoracic bristles. You do a test cross with a heterozygous female for all three genes, and you get the following progeny: spineless 82wild 380claret, spinless 130claret 18claret, hairless 80hairless, claret, spinless 323hairless 140hairless, spinless 12 The correct distance between sp - hl genes is: a. 0.25 umb. 0.36 umc. 41 umd. 25…8. You are working with a plant that shows blue pigmentation as a continuous trait that is encoded by two genes. For each gene, two alleles exist that can either contribute 1 or 0 doses of pigmentation. 8a. What is the maximum possible number of doses of pigmentation for a given plant? 8b. How many color phenotypes are possible in a dihybrid cross in this case? 8c. If there were six genes that controlled pigmentation in the same way, would there be more or fewer pigmentation phenotypes? How many would there be?
- 6. In certain plant species such as tomatoes and petunias, a highly polymorphic incompatibility gene Swith more than 100 known alleles prevents self-fertilization and promotes outbreeding. In this form ofincompatibility, a plant cannot accept sperm carrying an allele identical to either of its own incompatibility alleles. If, for example, pollen carryingsperm with allele S1of the incompatibility genelands onto the stigma (a female organ) of a plantthat also carries the S1allele, the sperm cannot fertilize any eggs in that plant. (This phenomenonoccurs because the pollen grain on the stigma cannotgrow a pollen tube to allow the sperm to unite withthe egg.)For the following crosses, indicate whether anyprogeny would be produced, and if so, list all possiblegenotypes of these progeny. a. ♂ S1S2× ♀ S1S2b. ♂ S1S2× ♀ S2S3c. ♂ S1S2× ♀ S3S4d. Explain how this mechanism of incompatibilitywould prevent plant self-fertilization.1. You have a line of rice that is true breeding for the recessive traits fo white rice (r) and dwarfisim (d). You cross a member of this line with an individual that is heterozygous at both loci and shows the dominant phenotypes of red grains (R) and tall height (D) yeilding the following progeny. 417 white grains-dwarf 403 red grains-tall 95 white grains-tall 85 red grains-dwarf a) what is the allelic configuration of the heterozygote? b) how far are the genes controlling grain color and plant height in (cM) c) what are the non cross over gametes d) what are the cross over gametes e) what genotype will result in white grains and tall heights (multplie answers) f) if you cross a heterozygote with the same allelic configuration as above, what is the probability that the offspring will have white grain and trall height? Give your answer to number to THREE decimal places not as a percentage (e.g 0.0446. The following is a linkage map of chromosome 5 for three genes in tomato: vs. If (leafy) Lf (normal) J (jointed} vs. į (jointless) W (non-wilty) vs. w (wilty) Lf W 17 11 The cross between the triple heterozygote (Lf J W/ If j w) and a triple homozygous recessive produced 600 progeny. Assume that there is no interference in the Lf-W region. Give the expected number of individuals for each of the following progeny types and show complete solutions. with crossover in the Lf-J and J-W regions with crossover in the Lf-J region with crossover in the J-W region without crossover in the Lf-W region a. b. C. d.