Imagine that you ve been invited to try out a new hoversuit, and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.40 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pik Q/A, where k is the electrical constant and Q/A is the charge density.)

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.2P: (a) Calculate the number of electrons in a small, electrically neutral silver pin that has a mass of...
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Imagine that you ve been invited to
try out a new hoversuit, and here s
how it works: Someone has set up a
large flat sheet, many kilometers
across, somewhere on the Earth,
and they ve charged the sheet up to
a uniform charge density of 8.40 x
10^-6 C/m2. You are issued a
special suit that you wear, and it has
controls on it which allow you to
charge the suit up to any number of
Coulombs (C), positive or negative,
that you might want. The idea is that
you can control the amount of
electrical repulsion (or attraction)
between the suit and the charged
sheet below you. What is the
strength of the electric field in the
region above the charged sheet?
(This is easy, since I m going to give
you the formula, which is E = 2 pi k
Q/A, where k is the electrical
constant and Q/A is the charge
density.)
Transcribed Image Text:Imagine that you ve been invited to try out a new hoversuit, and here s how it works: Someone has set up a large flat sheet, many kilometers across, somewhere on the Earth, and they ve charged the sheet up to a uniform charge density of 8.40 x 10^-6 C/m2. You are issued a special suit that you wear, and it has controls on it which allow you to charge the suit up to any number of Coulombs (C), positive or negative, that you might want. The idea is that you can control the amount of electrical repulsion (or attraction) between the suit and the charged sheet below you. What is the strength of the electric field in the region above the charged sheet? (This is easy, since I m going to give you the formula, which is E = 2 pi k Q/A, where k is the electrical constant and Q/A is the charge density.)
Same situation, but this time the
charge density in the sheet is 4.82 x
10^-6 C. Suppose your mass
(including the suit) is 84.4 kg. How
much charge must you give the suit
if you want to be able to just hover
stationary above the charged
sheet?
3.95E-03 C
5.17E-03 C
3.04E-03 C
2.13E-03 C
Transcribed Image Text:Same situation, but this time the charge density in the sheet is 4.82 x 10^-6 C. Suppose your mass (including the suit) is 84.4 kg. How much charge must you give the suit if you want to be able to just hover stationary above the charged sheet? 3.95E-03 C 5.17E-03 C 3.04E-03 C 2.13E-03 C
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