(II) Point a is 62 cm north of a –3.8 µC point charge, and point b is 88 cm west of the charge (Fig. 17–40). Determine (a) Vý – Va and (b) Ep – Ea (magnitude and direction). 62 cm FIGURE 17-40 b Q =-3.8 µC Problem 27. 88 cm
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- Suppose a speck of dust in an electrostatic precipitator has 1.00001012 protons in it and has a net charge of 5.00 nC (a very large charge for a small speck). How many electrons does it have?2%. (II) Point a is 62 cm north of a -3.8 uC poini charge, atld point b is 88 cm west of the charge (Fig. 17-40). Determine (a) ½ - V, and (b} Ể, - Ê, {magnitude and direction). 62 cm FIGURE 17-40 b Problem 27. Q=-3.8 µC 88 cm27. (II) Point a is 62 cm north of a -3.8 uC point charge, and point b is 88 cm west of the charge (Fig. 17-40). Determine (a) - V and (b) E,- E, (magnitude and direction). 62 cm FIGURE 17-40 Problem 27. b. 88 cm Q--3.8 pC
- (III) Two equal but opposite charges are separated by a distance d, as shown in Fig. 17-41. Determine a formula for VBA = VB - Va for points B and A on the line between the charges situated as shown. -d - FIGURE 17-41 -b- +q b- B Problem 30. A -9.ylsts Aia) Sib 2843 bluos r "(b91c M (O 26uq An initially neutral piece of plastic is has 1.09 x 1015 electrons removed from it. Determine the net charge of the plastic (in μC). no :(a)s 31 LOL OUG27. (II) Point a is 62 cm north of a -3.8 uC point charge, and point b is 88 cm west of the charge (Fig. 17-40). Determine (a) V - Va and (b) E, - E, (magnitude and direction). 62 cm FIGURE 17-40 b Q = -3.8 µC Problem 27. 88 cm
- (II) Determine the magnitude and direction of the electricfield at a point midway between a -8.0µ C and a +5.8 µccharge 6.0 cm apart. Assume no other charges are nearby20, (III) Two equal but opposite charges are separated by a distance d, as shown in Fig. 17-41. Determine a formula for VBA the charges situated as shown. V - VA for points B and A on the line between FIGURE 17-41 Problem 30.(II) What is the total charge of all the electrons in a 12-kgbar of gold? What is the net charge of the bar? (Gold has79 electrons per atom and an atomic mass of 197 u.)
- (III) The dipole moment, considered as a vector, points from the negative to the positive charge. The water molecule, Fig. 17-42, has a dipole moment p which can be considered as the vector sum of the two dipole moments, P¡ and pP2, as shown. The distance between each H and the O is about 0.96 x 10-10 m. The lines joining the center of the O atom with each H atom make an angle of 104°, as shown, and the net dipole moment has been mea- sured to be p = 6.1 × 10-30 C · m. Determine the charge q on each H atom. 104° H+ FIGURE 17-42 Problem 34. P2 A water molecule, H2O.(II) Three point charges are arranged at the corners of a square of side l as shown in Fig. 17–39. What is the poten- tial at the fourth corner (point A)? +Q -2Q FIGURE 17-39 +3Q A Problem 22.How many excess electrons are there in -10 C of charge?