EscM Inbox (2,372) - ftantill@ude Xapp.101edu.co← → C<STARTING AMOUNT56°FJRain off and onX22F-CHEM 103-510: Generax4 F24F3▬Aktiv Chemistry-572mol H₂What is the change in enthalpy when 1.25 moles of O₂ are reacted with an excess H₂of according to the following balanced chemical reaction:H₂O(l)ADD FACTORO SearchF4458g 0₂DII FS1KJConvert 33 psi to kpa | Quic X2Question 7 of 41H₂(g) + O:(g) → 2-ΔΗ= 572| kJ715CL2g H₂OF61.25ANSWER*18.02CHEM103- Lecture Notes --458F7mol O₂ mol H₂O2.020PrtScnFBRESET2-715JNXHomeF932.0Enthalpy of Formation Rear Xg H₂huleEnd F10PgUpF11+306 PODPgDnF120UpdateXSubmit6:56 PM12/6/2022D7teperJun

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IG AMOUNT X What is the change in enthalpy when 1.25 moles of O are reacted with an excess H₂ of according to the following balanced chemical reaction: H:O(1) -572 mol H: ADD FACTOR x( ) 458 90₂ kJ 2 - Question 7 of 41 H:(g) + O:(g) → 2 ΔΗ= 572| kJ 715 2 g H₂O 1.25 ANSWER 18.02 -458 2.02 mol O₂ mol H₂O RESET 2 -715 J 32.0 g H₂ <

IG AMOUNT X What is the change in enthalpy when 1.25 moles of O are reacted with an excess H₂ of according to the following balanced chemical reaction: H:O(1) -572 mol H: ADD FACTOR x( ) 458 90₂ kJ 2 - Question 7 of 41 H:(g) + O:(g) → 2 ΔΗ= 572| kJ 715 2 g H₂O 1.25 ANSWER 18.02 -458 2.02 mol O₂ mol H₂O RESET 2 -715 J 32.0 g H₂ <

Introductory Chemistry: A Foundation

8th Edition

ISBN:9781285199030

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter13: Gases

Section: Chapter Questions

Problem 137AP

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||| ANAN Microsoft O V The extraction of aluminum metal from the aluminum hydroxide found in bauxite by the Hall-Héroult process is one of the most remarkable success stories of 19th century chemistry, turning aluminum from a rare and precious metal into the cheap commodity it is today. In the first step, aluminum hydroxide reacts to form alumina (Al₂O3) and water: 2Al(OH)3(s) → Al₂O3(s) + 3H₂O(g) W Microsoft CHEMICAL REACTIONS Reaction sequence stoichiometry Microsoft 6.52.210... esc In the second step, alumina (Al2O3) and carbon react to form aluminum and carbon dioxide: 2Al₂O3(s) + 3C(s) → 4Al(s) + 3 CO₂ (8) Suppose the yield of the first step is 91.% and the yield of the second step is 85.%. Calculate the mass of aluminum hydroxide required to make 6.0 kg of aluminum. Be sure your answer has a unit symbol, if needed, and is rounded to the correct number of significant digits. Explanation Check 9,269 Q x10 HH 103 X OCT 24 ロ・ロ S OOO tv NONZA © 2022 McGraw Hill LLC. All Rights…
Constants: • c = 2.9979 x 108 m/s h = 6.626 x 10-34 J s per one photon • R = 8.314 J/(K mol) = 0.08206 L atm/(K mol) NA = 6.022 x 1023 particles/mol RH = 1.097 x 107 m1 = 2.178 x 10-18 J . . You have an aqueous Glucose solution that is 12.0% Glucose by mass. What is the molality of Glucose in the solution? Molar Mass of Water = 18.015 g/mol Molar Mass of Glucose 180.16 g/mol =
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Given the following data: AHr [CH:(g)] = -75 kJ mol· C(graphite) → C(g) AH = +712 kJ mol 1/2H2(g) – H(g) AH = +215.5 kJ mol 13. The bond enthalpy in kJ mol·' of the C-H bond in methane is A +375 B +412 C 375 D -412
→ C app.101edu.co STARTING AMOUNT esc 1 X 2 F2 CO #m 3 1 The average adult human burns 2.00 × 10³ kcal per day in energy. What is this rate in kJ per hour ? J ADD FACTOR * ( ) X 4184 F4 $ 4 cal 0 349 2.00 × 10³ F5 % 5 kJ Question 26 of 35 O 1000 2.01 x 10⁰ min M 6 31 = 0.001 F7 ANSWER 24 kcal/day O & 7 1.15 x 105 20.0 C F8 S 8 RESET 2 4.184 F9 kcal X 9 F10 60 hr F F11 8 Jan 21 F1Z2 3:17 6 delete Submit + backspac
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