If x[n]=1 for n=-1,0,1 and y[n]=1/3 for n=0,1,2 then the relationship between x [n] and y [n] is given by yln]=x[n/3] yln]=x[n/3 -1] O yln]=x[3n-1] O yln]=x[n/3+1] O yln]=3x[n-1] O yln]=x[n-1]/3 O yln]=x[n+1]/3 O

If x[n]=1 for n=-1,0,1 and y[n]=1/3 for n=0,1,2 then the relationship between x [n] and y [n] is given by yln]=x[n/3] yln]=x[n/3 -1] O yln]=x[3n-1] O yln]=x[n/3+1] O yln]=3x[n-1] O yln]=x[n-1]/3 O yln]=x[n+1]/3 O

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

If x[n]=1 for n=-1,0,1 and y[n]=1/3 for n=0,1,2 then the relationship between x [n]
and y [n] is given by
yln]=x[n/3]
yln]=x[n/3 -1] O
yln]=x[3n-1] O
yln]=x[n/3+1] O
yln]=3x[n-1] O
yln]=x[n-1]/3
yln]=x[n+1]/3 O

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