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- Eastern Hemlock Ring shake, which is the separation of the wood between growth rings, is a serious problem in hemlock trees. Researchers have developed the following function that estimates the probability P that a given hemlock tree has ring shake: P(A,B,D)=11+e3.680.016A0.77B0.12D where A is the age of the tree yr, B is 1 if bird pecking is present and 0 otherwise, and D is the diameter in. of the tree at breast height. Source: Forest Products Journal. a. Estimate the probability that a 150-year-old tree with bird pecking present and a breast height diameter of 20in., will have ring shake. b. Estimate the probability that a 150-year-old tree, with no presence of bird pecking and a breast height diameter of 20in., will have ring shake. c. Develop a statement about what can be said about the influence have on the probability of ring shake. d. Using the total differential, estimate the probability if the actual age of the tree was 160 years and the diameter at breast height was 25in., Assume that no bird pecking was present. Compare your answer to the actual value. Hint: Assume that B=0 and exclude that variable from your calculations e. Comment on the practicality of using differentials in part d.The Harbor Island Ferry leaves on the hour and at 15-minute intervals. The time, x, it takes John to drive from his house to the ferry has a uniform distribution with x between 10 and 20 minutes. One morning John leaves his house at precisely 8:00a.m O a. 0.5 O b. 0.3 O c. none of the above O d. 1 O e. 0.7= .7 and =.6. Test Ho: (P, - P2) =0 against H,:(P, – P2)>0 using a = .05
- .5 Calculate (×| – 1) dx. -5 O a. 17 O b. -10 None of the other choices are correct. O d. 10Alpha is usually set at .05 but it does not have to be; this is the decision of the statistician. Alpha is usually set at .05 but it does not have to be; this is the decision of the statistician. True FalseIF X-N(47, 225). Find the z-score of X=53 O A. -0.4 O B. 1.25 O C. None of these O D. -0.73 O E. 0.4
- hotos A survey of students at a college was asked if they lived at home with their parents, rented an apartment, or owned their own home. The results are shown in the table below sorted by gender. At = 0.05, test the claim that living accommodations are independent of the gender of the student. Live with Parent Rent Apartment Own Home Male 20 26 19 Connecti Female 18 28 26 secws10...e 34.jpg O A. Fail to reject the null hypothesis. There is not sufficient evident to warrant rejection of the claim that living accommodation and gender are independent. O B. Fail to reject the null hypothesis. There is sufficient evident to warrant rejection of the claim that living accommodation and gender are independent. O C. Reject the null hypothesis. There is not sufficient evident to warrant rejection of the claim that living accommodation and gender are independent. D. Reject the null hypothesis. There is sufficient evident to warrant rejection of the claim that living accommodation and gender are…H.: µ = 47.6 and H, : µ < 47.6 where u = the mean age of teachers at Ravenwood High School. The calculated p-value is 0.023. What conclusion will you make at a = 0.10? O Reject the H. O Fail to reject the H. O Reject the H. O Fail to reject the HaCalculate the relative frequency P(E) using the given information. (Round your answer to two decimal places.) A die is rolled 50 times with the following result: 1 and 2 never come up, 3 and 4 each come up 15 times, and 5 and 6 each come up 10 times. E is the event that the number that comes up is at least 4.
