Q: A flat surface of area 1.25 m2 is rotated through a uniform horizontal electric field of 5 N/C. What…
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Q: Inside the region in the shape ( Rectangular box) there is no electric charge. The uniform electric…
A: In the given system having a rectangular box placed such that electric field is passing…
Q: Consider a plane surface in a uniform electric field as in the Figure , where d=15 cm and Theta=70…
A: Given Data : The net flux through the surface is given as ϕ=6 N.m2C. The angle of the electric field…
Q: An electric field Ē = ax²î exists in a region. Total electric flux through a sphere of radius R…
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Q: The figure below shows a disk of radius 1.50 m is oriented with its normal unit vector n at an angle…
A: Given Radius of disk ,R = 1.50 m Electric field,E = 15.0*103 N/C Angle between area unit vector…
Q: Inside the region in the shape ( Rectangular box) there is no electric charge. The uniform electric…
A: According to Gauss’s law: ϕE=∫E.ds=Qencloseε0 Where, ϕE= Electric flux. E= Electric field.…
Q: In a symmetrical electric field of 58.3 x 101 N/C , a flat circle with a diameter of 30 cm is…
A: Given data: Electric field (E) = 58.3×101 N/C Diameter of the circle (d) = 30 cm = 0.30 m Circle's…
Q: An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45°. What…
A: Given:- E = 4.5N/C flat surface area = 0.30 m angle θ = 45o . electric flux = E * S * cos θ N M2 C-1…
Q: A non-uniform electric field having magnitude E = 3xi + 4j (E is in newtons per coulomb and x is in…
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Q: A flat surface of area 8 m^2 is rotated in a uniform electric field of magnitude E=320 N/C. The…
A: Given: The area of the surface is 8 m2. The magnitude of the uniform electric field is…
Q: An electric field Ē = axî + By txzk exists, in space where.a, B.Y are constant. Electric flux…
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Q: A flat surface of area 1.25 m2 is rotated through a uniform horizontal electric field of 4.20 N/C.…
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Q: An electric field with a magnitude of 3.50 kN/C is applied along the x-axis. Calculate the electric…
A: Electric Flux is the measure of the electric field through a given area. The component of the field…
Q: The uniform surface charge density ps nC/m² is presented on the plane z = 15cm. Find the electric…
A: We know that the Electric field due to the surface charge 'es' will be equal to…
Q: It is found that there is a net electric flux of 1.5 × 104 N ⋅ m2/C inward through a spherical…
A: Net electric flux,
Q: The figure shows a Gaussian cube of face area A immersed in a uniform electric field of magnitude E…
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Q: Compute for the magnitude of electric flux if the electric field whose magnitude is 5.25 N/C is…
A: Area of the rectangular surface, A = 6 m X 12 m…
Q: Consider the uniform electric field E = (4000 j + 3000 k) N/C. What is its electric flux through a…
A: Given the radius of the circular loop (R)=2.72m. The loop lies in the XY-plane. This means that the…
Q: An electric field (E=4.5N/C) passes through a flat surface area (0.30 m) with an angle of 45˚. What…
A: The electric flux is the number of electric field lines crossing through a given area. The electric…
Q: 1. Find the electric flux through the surface with sides of 15 cm X 15 cm shown in the figure below.…
A: The answers are below
Q: The total electric flux through a closed cylindrical (length = 1.2 m, diameter = 0.20 m) surface is…
A: Given Electric flux ∅=-5.0 Nm2/C Closed cyclinder length l=1.2 m diameter d=0.20 m
Q: An electric field given by E = 4 xi- 7yj pierces through a cubic Gaussian surface of edge length 2.0…
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Q: If the electric flux through a sphere is 10.0 Nm^2/C, what is the electric flux through a sphere of…
A: Given: The electric flux through a sphere is ϕ1=10.0 Nm2/C,
Q: A non-uniform electric field given by E =(6.0)i +(5.0y)j is in that space of a cube with side length…
A: Calculate the electric field. Calculate the area of the bottom surface.
Q: A flat sheet is in the shape of a rectangle with sides of lengths 0.400 m and 0.600 m. The sheet is…
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Q: An electric field given by E=[8j-(4y'+2y)k] NC is applied to a cube of length 1.8 mas shown in…
A: Electric field , E→ = 8j^ -(4y2 +2y)k^ side length , L = 1.8 m To find = Electric flux through the…
Q: A square 10 cm long is in a region where there exists a uniform 2.0 kN/C electric field normal to…
A: Given data: Side of square (s) = 10 cm = 0.1 m Electric field (E) = 2.0 kN/C = 2000 N/C Angle…
Q: Calculate the electric flux through a trapezoid, with measurements of 4 cm at the smaller base, 7 cm…
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Q: A rectangular surface of sides 10 cm and 15 cm is placed inside a uniform electric field of 25 V/m,…
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Q: A flat surface with an area of 1.25 m² is rotated through a uniform horizontal electric field of 5…
A:
Q: Consider a plane surface in a uniform electric field as shown in the figure, where d =20 cm and the…
A: The electric field is an area within which when a charged particle enters, a force gets exerted on…
Q: A flat circle of radius 200 mm is placed in a uniform electric field of magnitude 20500 mN/C. What…
A: Given data; Circle of radius r =200 mm=0.2 m uniform electric…
Q: Consider a cube with edge length L immersed in a uniform electric field E along the x-direction as…
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Q: A plane with a surface area of 15 m² makes an angle of 35 degrees with it. What will be the electric…
A: Given information: The surface area of the plane (A) = 15 m2 The angle the plane makes (θ) = 350 The…
Q: What is the flux due to electric field E = 3 × 103,NC−1 through side of the square 10cm , when it is…
A: Given : E = 3 × 103 NC–1 Side of square (S) = 10 cm = 0.1 m. Area of square (A) = (side)2 = (0.1)2 =…
Q: An electric field of intensity 3.50 kN/C is applied along the x-axis. Calculate the electric flux…
A: Given data: Intensity of electric field is, E=3.50 kN/C =3.50×103 N/C. Width of rectangular plane…
Q: A cylinder of radius R has a charge density given by p = Po/r where po is a constant, for r R. Find…
A: Question 1 Given data The radius of the cylinder is R
Q: What is the total flux passing through a 10 cm × 6 cm surface in a region where the electric flux…
A: Electric flux is defined as the product of the electric field and the specified area. Electric flux…
Q: A flat surface of area 6.5 cm2 in the x -y plane sits in a uniform electric field E ⃗=2i ̂+3j ̂+5k ̂…
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Q: If the electric field is known everywhere on a closed surface, the quantity of charge enclosed by…
A: From question: The quantity of charge enclosed by the surface can be calculated by Gauss Law:
Q: A uniform electric field of strength E = 334 N/C passes through a flat surface at an angle of 0.880…
A: To find the area of the surface in given conditions. We are given with E=334 N/C angle θ=0.880…
Q: In a symmetrical electric field of 58.3 x 10 , a flat circle with a diameter of 30 cm is positioned.…
A: Calculate the area of the circle. A=πD22=π30 cm×10-2 m1 cm22=0.0706 m2 Here, A is the area of the…
Q: Consider the uniform electric field E = (3.0ĵ + 7.0k) × 103 N/C. What is its electric flux (in N -…
A: Given:- The uniform electric fieldE→= 3.0 j^+7.0 K^×103 N/C The circular area of radius of 5 m…
Q: The net electric flux crossing a closed surface is always zero. True or false?
A: The flux of a vector field through a closed surface is always Zero if there is no net charge…
Q: In Figure below, consider a plane surface in a uniform electric field, where d = 15 cm and θ = 70o .…
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Q: A uniform electric field 98 x 103 N/C passes through a circular surface of radius 12.2 cm as shown…
A: The formula for the electric flux is: From the diagram, the angle between the area vector and the…
If the electric field is given by 6i+3j+4k calculate the electric flux through a surface of area 20 units lying in y-z plane.
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- An infinite cylindrical conductor has an inner radius ra =57.9mm and an outer radius 70.4mm. The conductor has a linear charge density of A₁ =136. On the axis of the cylinder is an infinite line charge with linear charge density ₂ = -9€. Determine the electric field magnitude at the point r = 31.03mm (in) C OThe electric field at a distance of 0.154 m from the surface of an insulating solid sphere of radius 0.385 m is 1970 N/C. Assuming that the charge on the sphere is uniformly distributed, a) what is the charge density within it? b) Calculate the electric field inside the sphere at a distance of 0.150 m from the center.A disk with a radius of 0.10 m is in a uniform electric field with a size E = 2x10 ^ 3 N / C. The normal unit vector of the disk makes an angle of 30 degrees with E. How much is the electric flux through the disk?
- The electric field of a thin uniformly charged disk of radius 2.5 m very close to disk center is 263 N/C. The disk is centered on the xy plane. Calculate the magnitude of the electric field ( in N/C) on the z-axis at a distance 4 m from the center of the disk.A long nonconducting cylinder (radius 6.0 mm) has a nonuniform volume charge density given by ar, where a= 6.2 mC/m' and r is the distance from the axis of the cylinder. What is the magnitude of the electric field at a point 2.0 mm from the axis?Positive charge is distributed in a sphere of radius R that is centered at the origin. Inside the sphere, the electric field is Ē(r) = kr-1/4 f, where k is a positive constant. There is no charge outside the sphere. a) How is the charge distributed inside the sphere? In particular, find an equation for the charge density, p. b) Determine the electric field, E(r), for r > R (outside the sphere). c) What is the potential difference between the center of the sphere (r = 0) and the surface of the sphere (r = R)? d) What is the energy stored in this electric charge configuration?
- A cube with edge lengths 1.6 m contains positively charged particles. Consider a Gaussian surface ofexactly the same dimensions surrounding the cube. The electric field caused by the charges is normalto all the faces of the Gaussian cube. If the electric field at each face of the cube has a magnitude of750 N/C, determine the average volume charge density in the cube.A closed surface with dimensions a = b = 0.208 m and c = 0.3328 m is located as in the figure. The electric field throughout the region is nonuniform and defined by E (a + Bx²) î where x is in meters, a = 5 N/C, and 3 = 6 N/(C · m²). Y E Answer in units of C a x k What is the magnitude of the net charge enclosed by the surface? Answer in units of C. part 2 of 2 What is the sign of the charge enclosed in the surface?The volume charge density of a sphere of Radius R is directly related to the radius of the sphere as given by the equation p(r) = br where b is a positive integer. What would be expression for the electric field at r = 1/2 R from the center of the sphere?
- A circular surface with a radius of 0.066 m is exposed to a uniform electric field of magnitude 1.90 × 104 N/C. The electric flux through the surface is 52 N·m2/C. What is the angle between the direction of the electric field and the normal to the surface?An electric field 7 N/C is passing through a region of area 2.1 m² in the xy-plane. If the electric field makes an angle of 56° with respect to the area vector perpendicular to the region, calculate the electric flux magnitude (in N-m²/C) through the region.A uniform electric field ai + bj intersects a surface of area A. What is the flux through this area if the surface lies (a) in the yz plane? (b) in the xz plane? (c) in the xy plane? The electric field everywhere on the surface of a thin spherical shell of radius 0.750 m is measured to be equal to 890 N/C and points radially toward the center of the sphere. (a) What is the net charge within the sphere's surface? (b) What can you conclude about the nature and distribution of the charge inside the spheri- cal shell?