If 1.00 molmol of argon is placed in a 0.500-LL container at 24.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2a=1.345(L2⋅atm)/mol2 and b=0.03219L/molb=0.03219L/mol. Express your answer to two significant figures and include the appropriate units.
If 1.00 molmol of argon is placed in a 0.500-LL container at 24.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2a=1.345(L2⋅atm)/mol2 and b=0.03219L/molb=0.03219L/mol. Express your answer to two significant figures and include the appropriate units.
Principles of Modern Chemistry
8th Edition
ISBN:9781305079113
Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Publisher:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
Chapter10: Solids, Liquids, And Phase Transitions
Section: Chapter Questions
Problem 6P
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If 1.00 molmol of argon is placed in a 0.500-LL container at 24.0 ∘C∘C , what is the difference between the ideal pressure (as predicted by the ideal gas law ) and the real pressure (as predicted by the van der Waals equation)? For argon, a=1.345(L2⋅atm)/mol2a=1.345(L2⋅atm)/mol2 and b=0.03219L/molb=0.03219L/mol.
Express your answer to two significant figures and include the appropriate units.
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