I Review T Constants I Periodic Table Part A A running mountain lion can make a leap 10.0 m long, reaching a maximum height of 3.0 m. What is the speed of the mountain lion just as it leaves the ground? Express your answer with the appropriate units. HA ? Vi = Value Units Submit Request Answer Part B At what angle does it leave the ground? Express your answer in degrees.
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- #3) Use the figure for projectile motion. You are working on your jump shot. The magnitude of the initial velocity for the ball is vo = 9.5 m/s and the angle you launch it is at 37.0°. Note the ball's initial starting height is h = 1.90 m. Most of your points will come from setting up the equations correctly and your algebra manipulation prior to plugging in numbers. Numbers last. Report answers to 3 sig figs. ECANSU h (A) Find the total time the ball is in the air, from h to the time it hits the ground. (B) Find the maximum horizontal distance the person can throw ball given these conditions.A cannonball is shot with an initial speed of 66 m/s and 37.0º angle with respect to the ground. How long does it take for the ball to reach its the maximum height, in seconds? Use g = 10.0 m/s2. Your answer needs to have 2 significant figures, including the negative sign in your answer if needed. Do not include the positive sign if the answer is positive. No unit is needed in your answer, it is already given in the question statement.The 2010 Soccer World Cup played here in South Africa will always be a history to remember. That was when Simphiwe Tshabalala scored a beautiful long range shot when Bafana Bafana was playing against Mexico in the opening game. After kicking the ball, it touched the goal-line (at ground level) 35.00 m from where he kicked it, and the maximum height reached by the ball was 6.50 m. Use the above information to answer questions 12 to 15. Calculate: 12. Calculate the time at which the ball reached this maximum height. 13. The angle at which Tshabalala kicked the ball relative to the ground. 14. The vertical component of the initial velocity, Voy. 15. The initial velocity at which he kicked the ball.
- A ball is thrown at an initial height of 65 feet at an initial velocity of 75 feet/second at an angle of 65 degrees. Given the parametric equations yY = - - 16t + Vo · Sin(0)t + ho and x = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. seconds. b. When will the object hit the ground? feet. c. How far horizontally will the ball be when it hits the ground? seconds. d. When will the ball be at its maximum height? e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?5. A ball is thrown following a projectile motion, it is known that the horizontal distance (range) the ball can travel is given by R= sin 24, where r is the range (in feet), vy is the initial speed (in ft/s), B is the angle of elevation the bal is thrown, and g=32 ft/s? is the acceleration due to gravity. a. Express the new range in terms of the original range when an angle 8 (0< @ < 45°) is doubled. b. If a balt travels a horizontai distance of 20 t when kicked at an angle of a with initial speed of 20/2 fus, find the horizontal distance it can travel when you double z. Hint: use result of item (a).In the sport of billiards, event organizers often remove one of the rails on a pool table to allow players to measure the speed of their break shots (the opening shot of a game in which the player strikes a ball with his pool cue). V. o h d The top of a pool table is a height h = 3.25 ft from the floor. If a player's ball lands a distance d 14.75 ft from the table edge, what is her break shot speed vo? 12.3 Vo = mph Incorrect At what speed v did her pool ball hit the ground? 4.21 mph = Incorrect
- 1つ7 3. An object undergoes motion in 2 dimensions under a constant acceleration of "-2.50 m/s at an angle of 50.0° with respect to the + x direction. It also has an initial velocity of vi = 7.00 m/s at an angle of 10,0° The object begins at the coordinates (0, 0). a) What are the coordinates of the object at t = 7.00 s? Want Cx, y) at t =?4 4tzテメ0チ=XT vse this Con Vxi = \V;l cos v +ハ Ay=lalsin Ga b) What is its total velocity vector of the object as a magnitude and direction at t = 7.00 s? a) Ov= Ton5. A ball is thrown following a projectile motion. It is known that the horizontal distance (range) the ball can travel is given by R = sin 20, where r is the range (in %3D feet), vo is the initial speed (in f/s), 0 is the angle of elevation the ball is thrown, and g=32 ft/s? is the acceleration due to gravity. a. Express the new range in terms of the original range when an angle 8 (0< 0 < 45°) is doubled. xiii b. If a ball travels a horizontal distance of 20 ft when kicked at an angle of a with initial speed of 20V2 ft/s, find the horizontal distance it can travel when you double a. Hint: use result of item (a).A golf ball was hit and follows a trajectory path. It travels 28m/s upon hitting at 400 with respect to horizontal ground. 1. Calculate the maximum height that the ball will reach above the ground. 2. Calculate the range of the ball upon hitting back to ground. 3. Calculate the total time that the ball is in the air.
- Provide the complete solution and figure.No unit/wrong unit, wrong answer. PROBLEM:A ball is kicked at the edge of a cliff with a magnitude of 20m/s at angle of 40o from the horizontal. It hits a vertical wall 50m away and lower than the elevation of the cliff. Determine the vertical height from the point where the ball hits the wall to:a. the level of the cliffb. its highest point1. A projectile is thrown with a speed of 100 ft/s in a direction 30 degrees above the horizontal. Illustrate the projectile motion and answer the following: a. How many feet will it rise? b. How many feet will the maximum horizontal displacement be?stion A postman leaves the post office and drives 1.6 km in the north direction. He then drives in a direction 60.0° south of eact for 5.9 km (see Figure) North out of 60° East Post office What is his resultant displacement from the post office (in vector form)? O a. -3.51 mi + 2.95 mj Ob. 5.90 mi+ 1.60 mj Oc. 2.95 mi+-3.51 mj Od. None of the above O e. 1.35 mi- 5.11 mj