I did not understand this c++ code, please help me solve my confusion. In the first void function, we can enter a number for *input, but why in the second void function use *val to calculated the value I entered for the first void function. I think one is *input, and the second one is *val. #include using namespace std; void getNumber(int *input); void doubleValue(int *val); int main() { int number; getNumber(&number); doubleValue(&number); cout<<"That value doubled is"<>*input; } void doubleValue(int *val) { *val *=2;
I did not understand this c++ code, please help me solve my confusion. In the first void function, we can enter a number for *input, but why in the second void function use *val to calculated the value I entered for the first void function. I think one is *input, and the second one is *val. #include using namespace std; void getNumber(int *input); void doubleValue(int *val); int main() { int number; getNumber(&number); doubleValue(&number); cout<<"That value doubled is"<>*input; } void doubleValue(int *val) { *val *=2;
C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter6: User-defined Functions
Section: Chapter Questions
Problem 1TF: Mark the following statements as true or false:
a. To use a predefined function in a program, you...
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I did not understand this c++ code, please help me solve my confusion.
In the first void function, we can enter a number for *input, but why in the second void function use *val to calculated the value I entered for the first void function. I think one is *input, and the second one is *val.
#include <iostream>
using namespace std;
void getNumber(int *input);
void doubleValue(int *val);
int main()
{
int number;
getNumber(&number);
doubleValue(&number);
cout<<"That value doubled is"<<number<<endl;
return 0;
}
void getNumber(int *input)
{
cout<<"Enter an integer number:";
cin>>*input;
}
void doubleValue(int *val)
{
*val *=2;
}
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