HPro (aq) + OH-(aq) H2O (1) + Pro-(aq) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. Calculate the pH of this final solution.
HPro (aq) + OH-(aq) H2O (1) + Pro-(aq) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. Calculate the pH of this final solution.
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter16: Principles Of Chemical Reactivity: The Chemistry Of Acids And Bases
Section: Chapter Questions
Problem 116IL: Amino acids are an important group of compounds. At low pH, both the carboxylic acid group (CO2H)...
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Please solve questions 7 & 8 based on the following data for [HPro], [NaOH], and [NaPro]. Thanks!
![:-
the
end
O.100 M
(80.0+ 20.0)m2
[NaOH]
(80.0+20.0) mz
2.8 um
I Na Poo] =
O. 028 M
180.0+20.0) m2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F476b5cb0-a3fb-4b49-8c26-098fb10da8e5%2F950a0954-78f8-4706-ad42-62a6e13d7dde%2F7h8jocp_processed.png&w=3840&q=75)
Transcribed Image Text::-
the
end
O.100 M
(80.0+ 20.0)m2
[NaOH]
(80.0+20.0) mz
2.8 um
I Na Poo] =
O. 028 M
180.0+20.0) m2
![In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH-(aq)
→ H2O (1) + Pro- (aq)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka
equation to solve for the value of [H*].
8)
Calculate the pH of this final solution.
9)
Write the dissociation reaction for the weak base LiPro (Pro'-) in water.
10) Write the mass action expression for this equation, which is equal to K.
11) Since Kw = Ka × Kb., solve for the mathematical value of Kb.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F476b5cb0-a3fb-4b49-8c26-098fb10da8e5%2F950a0954-78f8-4706-ad42-62a6e13d7dde%2Fwdy01ef_processed.png&w=3840&q=75)
Transcribed Image Text:In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a
spectator ion and has been omitted.)
HPro (aq) + OH-(aq)
→ H2O (1) + Pro- (aq)
6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end
of this "big change" reaction. (The LR concentration will be zero.)
7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka
equation to solve for the value of [H*].
8)
Calculate the pH of this final solution.
9)
Write the dissociation reaction for the weak base LiPro (Pro'-) in water.
10) Write the mass action expression for this equation, which is equal to K.
11) Since Kw = Ka × Kb., solve for the mathematical value of Kb.
12) Calculate the following values for a 0.138 M Ca(Pro)2 solution:
(a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table)
(b) the pH of a 0.138 M Ca(Pro)2 solution.
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