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A: Given values: Width of the region, ∆x=10-12 m Plank's constant, h=6.626×10-34 J·s Mass of electron,…
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A: According to the uncertainty principle, ∆x∆p=h2π We know that, ∆x∆p≥h4π
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A: We know, the given wave function is of the form Hence, k=5.00×1010m-1. The de-Broglie wavelength…
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A: ψ(x)= A sin(5 x 1010x)
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A: The wavelength, λ=6.1 cm=6.1×10-2 m The mass of the billiard ball, m=0.400 kg
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Q: If the electron is positioned in the region of width 10-12 m then calculate the time constant of the…
A: Given: The width of the region is 1x10-12 m.
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A: The velocity is given by, λν=c Thus, the frequency will be, ν=3×108 m·s-110-12 m =3×1020 s-1
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- A spherical virus has a diameter of 50 nm. It is contained inside a long, narrow cell of length 1 x 10-4 m. What uncertainty does this imply for the velocity of the virus along the length of the cell? Assume the virus has a density equal to that of water.If the position of an electron in a membrane is measured to an accuracy of 3.58 µm, what is the electron's minimum uncertainty in velocity (in m/s)? a) If the electron has this velocity, what is its kinetic energy in eV? b) What are the implications of this energy, comparing it to typical molecular binding energies?A neutron is confined in a deuterium nucleus (deuteron) of diameter 3.1 x 10-15 m. Use the energylevel calculation of a one-dimensional box to calculate the neutron’s minimum kinetic energy. What is the neutron’s minimum kinetic energy according to the uncertainty principle?
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