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- Artificial intelligence Develop a Word2Vec Language Model Use a corpus , to build a Word2Vec Language Model, using Python. Each student should learn what is Word2Vec by him/herself. The language model will be a set of words and a vector of numbers (called Word Embeddings) for each word. The language model can be easily used in Python. After building the language model, each student should demonstrate it by: (1) finding similar words to a given word, and (2) Finding the cosine similarity between two words.1. For each of the following regular expressions find a language (i.e., a set of strings) over A = {a,b,c} that can be represented/described by that expression. a. a*bc + bc* b. b*aaac* а. b.Let G = ({S,A,B,C,D,E,Z},(0,1),R,S),where R = {S → E | Z; E → A | C; A → 01B | 0A | ; B → 1B |10A; C →10D |1C |; D →01C |0D; Z →0Z1 |}.(a) Describe the language L (in English) that is generated by the CFGG.(b) Prove that the language L generated by the CFG G is not regular.Hint: use the fact that regular languages are closed under unionand prove that one component of the language is not regular bythe Pumping Lemma.
- 7. Show that, CFLTM = {(M) | M is a TM and L(M) is a context free language } is undecidable.Draw NFA for the language L={ anb | n≥5 } defined over Σ={a,b}. Implement it using LEX/FLEX and YACC/BISON. Test it with the strings ab, aaaaab, aabb, aaaaaaab and aaaaaabb. Give the source code and the runtime screen with compilation and execution steps. course name compiler constructionsi4. Consider the following languages. ANFAFIN = {{N) | N is an NFA and L(N) is finite} EREX = {(R) | R is a regular expression and L(R) = 0} • EQREX = {(R1, R2) | Ry and R2 are regular expressions and L(R;) = L(R2)} • EQ NFAFINSET = {(N,U) | N is an NFA, U is a finite set of words, and L(N) = U} • ALLREX = {{R) | R is a regular expression and L(R) = {0,1}*} %3D (a) Answer the following questions based on the NFA N as shown below. Simply say yes or no. 1 (i) Is (N) € ANFAFIN? (ii) Is (0|1)") € EREX? (iii) Is (00", 0*0) € EQREX?
- 4. Consider the following languages. ANFAFIN = {(N) | N is an NFA and L(N) is finite} • EREX = {(R) | R is a regular expression and L(R) = 0} • EQREX = {(R, R2) | R, and R2 are regular expressions and L(R) = L(R)} • EQ NFAFINSET = {{N,U) | N is an NFA, U is a finite set of words, and L(N) = U} • ALLREX = {(R) |R is a regular expression and L(R) = {0, 1}*} %3D (a) Answer the following questions based on the NFA N as shown below. Simply say yes or no. (i) Is (N) E ANFAFIN? (ii) Is (0|1)*) E EREX? (iii) Is (00*, 0*0) € EQREX?. Prove that the intersection of two context-free languages is not necessarily context-free. This is unlike the case of regular languages which are closed under intersections. Hint: Do something similar to what we did on Activity #21 to show something about two of the languages below and then use what we proved in class about the remaining language. Write several sentences to explain your reasoning. L₁ = {ww has the form a"b"c" for some whole numbers n and m} L2 = {ww has the form amb"c" for some whole numbers n and m} L3 = {w|w has the form a"b"c" for some whole number n}3. Consider L = { a²b²ncp | p 0}. Prove L is not a context-free language.
- For the language, draw the corresponding DPDA. L ={x ∈ {a, b}* | na (x) < nb (x)}.Let Cbe the language over {a, b,c, d, e, f} accepting all strings so that: 1.There are precisely two b’s in the string. 2.Every a is immediately followed by an odd number of e’s. 3.Every d is immediately followed by an even number of f’s. 4.e’s and f’s don’t occur except as provided in rules 2 and 3. 5.All a’s occur after the first b. 6.All d’s occur before the second b. 7.In between the two b’s there are exactly twice as many a’s as d’s.HINT: Don’t be intimidated by the number of rules. The way they interact actually helps you simplify the number of cases you have to deal with while constructing this grammar. a. Construct a context-free grammar generating C.Explain how your construction accounts for each rule. b. We could eliminate one rule from Cand make it regular. Which rule would that be, and why would it work? You do not need a formal proof, but you do need an explanation.> Let L = {a"b":n>0} a. Show that L² is a context-free language. b. Show that L' is a context-free language.