H.W4 The single-phase full wave controlled rectifier has a purely resistive load of R and the delay angle is α=27/3, and I₁=10A and PL=100Watt determine: -The efficiency, -The ripple factor RF, -The peak inverse voltage PIV of thyristor
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- A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consisting series connected a resistor and an inductance from a 70.7V (RMS), 50HZ sinusoidal AC source. The firing delay of the thyristor is 90° and the load values are R=10Q, L=0.1 H. Define the load current expression and draw the load current by calculating for first two periods. And calculate the average values of the load voltage and current.A single phase – half wave controlled rectifier with freewheeling diode is supplying a load consistingseries connected a resistor and an inductance from a 70.7V (RMS), 50Hz sinusoidal AC source.The firing delay of the thyristor is 90° and the load values are R=10Ω, L=0.1 H. Define the loadcurrent expression and draw the load current by calculating for first two periods. And calculate theaverage values of the load voltage and current.92) For three - phase half-wave Controlleed rectifier Shown in he figure: 1. Derive a fomu la for mean load Voltage. 2. praw the wave form of vo, i,,i, iy and voltage across thyristor 1 (r.) assuming highly inductive load and d = 120
- Design a single-phase full wave bridge rectifier with input voltage of 100v and inductive load of 10ohm and 40mH a. Show the waveform relation between the I/P and O/P b. Calculate the average O/P voltage c. Calculate the rms currentA half-wave rectifier with ohmic load given in the figure below feeds a 50 Q load and the peak value of the source voltage is 311V and the frequency is 50 Hz. Accordingly, find the following desired circuit parameters: a) Effective (rms) voltage of the source, b) the peak current of the load, c) Average stress of the load, d) Average current of the load, e) The effective (rms) voltage of the load, f) Effective (rms) current of the load, g) Power of the load + vD RPower supply circuit is delivering 0.5 A and an average voltage 20 V to the load as shown in the circuit below. The ripple voltage of the half wave rectifier is 0.5 V and the diode is represented using constant voltage model. The smoothing capacitor value is equal to 220V rmsh soHz} VL-DC =20V 0.01 F 0.02 F 0.0167 F None of the above
- P) For single - phase half-controlled bridge rectifier shown in the figure: 1. Derive a formula for mean load Voltage. 2. Draw the waveforms of Ve,is,iz, i3, iy and io assuming highly inductive Load and =45. T. T3 DyNote: Answer All question 1: A) For a single-phase half-wave uncontrolled rectifier with (RL) load, find the rms value of the output voltage (V) and form factor (FF%) with supply voltage: v,(t) = 10 sin(wt). Draw the circuit diagram and sketch the voltages and current waveforms. The conduction angle B = 220°. %3D3 Given the bridge-type full-wave rectifier circuit shown 220V 60Hz 220V:Es Es D1 D2 D3 D4 The load resistor is 220 and the transformer average current is 300mA. Determine: (a) Average value, RMS value, and frequency of load voltage VRL. (b) Average current and PIV of each diode. RL
- H.W:- For a single phase half wave uncontrolled rectifier if the input supply voltage is (v= 310 sin314t), at frequency (f= 50 Hz). Then determine the followings:- Vm. Vmean- i. Draw the rectifier circuit. un %3D ii. Draw the input and the output voltages waveforms. iii. Determine the mean and rms values of the output voltage. s Ec iv. If the load is (R=10 S), then determine the mean and rms values of the current. 2019Question 3) An ohmic loaded half-wave controlled rectifier given in the figure below feeds a 25 Q load and the peak value of the source voltage is 350V and its frequency is 50 Hz. Accordingly, find the following desired circuit parameters: a) Effective (rms) voltage of the source, b) the peak current of the load, c) Average stress of the load, d) Average current of the load, e) The effective (rms) voltage of the load, f) Effective (rms) current of the load, g) Power of the load K RH.W3 The single-phase full wave controlled rectifier has a R-L load with R= 0.552 and L= 6.5mH. The input voltage V, 220V at 50Hz. The delay angle is a-30, plot the input and output waveforms. Then determine: -The average thyristor current -The rms thyristor current -The output rms current -The average output current - The efficiency NOTE: Drive any formula that used in solution