Given the initial partial pressures of (Peas) = 0.0500 atm, (Prs) = 0.150 atm, and (Paz) 0.250 atm at 250°C for the following reaction, what must each equilibrium partial pressure be? %3D %3D PAs (a) + PClh (@) + Ch (a) K, = 2.15

Chemistry: Principles and Reactions
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Chapter12: Gaseous Chemical Equilibrium
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Problem 11QAP: Write an equation for an equilibrium system that would lead to the following expressions (ac) for K....
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Determine the concentrations. The following answer was given. I just need help how solve step by step until i arrived with this given answer. PCL- 0.228 ; PCL -0.177 CL2 -0.277
Given the initial partial pressures of (Peas) = 0.0500 atm, (PpB) = 0.150
atm, and (Paz = 0.250 atm at 250°C for the following reaction, what must
each equilibrium partial pressure be?
%3D
PAls (a) + PCly (a) + Ch (a)
K, = 2.15
Transcribed Image Text:Given the initial partial pressures of (Peas) = 0.0500 atm, (PpB) = 0.150 atm, and (Paz = 0.250 atm at 250°C for the following reaction, what must each equilibrium partial pressure be? %3D PAls (a) + PCly (a) + Ch (a) K, = 2.15
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