Given the expression F = A’B + CD + {(A+B)’ [(ACD) + (BE)’]} ,draw its logic implementation using the basic logic gates. Then use NAND gates, NOR gates, or combinations of both to implement the same expression
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- An equation in reduced SOP form, is F=AB+B'C+A'C'. I need to draw a logic circuit F using NOT/AND/OR and logoc circuit F using all NAND gates. Thank you for the help. I understood the previous types of gates but I am confused on how to draw these circuits.T: Answer thne f. questions: 1) The hexadecimal number ´Al' has the decimal value equivalent to (A) 80 (B) 161 (C) 100 (D) 101 2) The output of a logic gate is 0 when all its inputs are logic 1. The logic is either (A) a NAND or an EX-OR (B) an OR or an EX-NOR (C) an AND or an EX-OR (D) an NOR or an EX-NOR 3) The Gray code of the Binary number 1100111 is (A) 1011011 (B) 1010100 (C) 1001001 (D) 101101 4) When simplified with Boollean Algebra (a+b)(a+c) simplifies to (A) a (B) a+a(b+c) (C) a(1+bc) (D) a+bc 5) -31 is represented as a sign Binary number ( using Sign-magnitude form ) equal to (A) 00011111 (B) 10101001 (C) 01110010 (D) 00101101 6) The Binary number 110111 is equivalent to decimal number (A) 25 (B) 55 (C) 26 (D) 34 7) With 4 bit, what the range of decimal values if the number is 2's complement signed number. (A) -32 to +31 (B) -2 to +1 (C) -8 to +7 (D) None of theseDraw a logic diagram using only two-input NAND gates to implement the following expression: (AB + A'B') (CD'+C'D)
- Construct a circuit diagram that checks whether the two numbers A and B are in the ratio of 2:3. Also, derive the final Boolean equation for the function. F = 1 if A: B = 2: 3,0 otherwise Here, A and B both are 3 bit binary numbers. NB: You cannot use the IC of comparator, meaning for the comparison part, you need to draw the gate level diagram. You can use block level diagrams for the rest of the parts.B) Draw the logic circuit for each of the following: 3) The expression (XY + Z + XYZ + X) by using NAND gate orSimplify the following expressions, and implement them with two-level NAND gate circuits: (a) AB'+ABD + ABD’+A’C’D'+A’BC' (b) BD + BCD'+AB’C’D' Draw a logic diagram using only two-input NAND gates to implement the following expression: (AB + A’B') (CD'+C°D)
- Logic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions.Task 1: 2-to-1 LINE MULTIPLEXER DESIGNA) Write the truth table of 2-to-1 line multiplexer.B) Draw the circuit diagram by using only NAND & NOT GATES.C) Simulate the circuit that you found in part B.Logic Gates:* 7404LS (NOT)* 7408LS (AND)* 7432LS (OR)* 7400LS (NAND)* 7402LS (NOR)* 7486LS (EX-OR)Or you can use 74HCxx versions. Task 2: 4 INPUT PRIORITY ENCODERa) Write the truth table.b) Find the outputs in terms of min terms using minimal expression.c) By using K map, find the simple/simplest expression of theoutputs.d) Draw the circuit diagram. (Simulation design will be accepted.)e) Simulate the circuit & explain your results. (Please do notdesign separate simulations for each output. You should design ONEsimulation including all inputs and outputs.)parity generator design, construct and test a circuit that generates an even parity bit ffrom four messages bits . use XOR gates. adding one more XOR gate, expand the circuit so that it generates an odd parity bit also.
- 3. Draw a logic diagram using only two-input NAND gates to implement the following expression: F=(AB + A'B')(CD' + C'D)The following logic gate represents: a) Exclusive OR logic gate, b) NAND logic gate, c) AND logic gate. A o d) Anticoincidence logic gate, e) NOR logic gate, f) OR logic gate. D- BOConvert the following logic gate circuit into a Boolean expression, writing Boolean sub-expressions next to each gate output in the diagram: C DD