Given the circult below. , (t) - 3u (t). 1Ω is 2Ω 0.2 H
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Given: is(t)=3u(t)
What is the total power dissipated by the current source at steady state in W?
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- What's the rise time for this system with its closed-loop poles as shown? 14 -6 -4 12 -j6 Select one: a. 0.607 sec b. 3.14 sec C. 1.80 sec d. 0.254 seC e. 0.554 secWrite down the differential equations describing the loop currents of the given circuit. Assume clockwise rotation and i passes through the voltage source. R1 2 Ohms L1 C1 0.5F 0.3H Vs V R3 6 Ohms R2 10 Ohms C2 0.25Fin V1 R2 100k SINE(0 10 100) R1 100k D1 D V2 0 out D D2 V3 0 DC offset[V]: 0 Amplitude[V]: 10 Freq[Hz]: 100 T delay[s]: Theta[1/s]: Phi[deg]: Ncycles: anter 2019-2220 Figure 3-5 Clipper Circuit for LTSPICE Simulation C4. To specify the type of simulation, select "Simulate>>Edit Simulation Cmd" from the menu. Choose "Transient" and enter 30m for Stop time, 0 for Time to start saving data, and 1m for Maximum Timestep. Click OK. C5. Click Run to start the analysis. C6. Place two voltage probes (voltage probes appear when placed on a wire during simulation), one at the input side (at the top of V1) and another at the output side (at the top of D2) of the circuit. What difference do you observe between the input and the output waveforms?
- Solve the following electric circuit given in the following figure by using echlon or reduced echlon form You may use KVL & KCL to form linear equations involving i1, i2, is 20 2 10 2 Q 80 V, 102 90 V P 152google.com/forms/d/e/1FAlpQLScF2Wzu92iVI-tEM2nxdhqXrGdR460G4QCTxaUZZeC678PqTg/formResponse مطلوب /06 *:The potential at point P due to Q1 and Q2 is Q, = 1x10-12C 0.5 m 0.5 m Qz = 1x10-12C %3D 50 cm 0.01797 V Ov O -0.01271 V O 0.01271 V O Insert PIC F10 F11 F12 F6 F7 FB Backspace 9 € P Enter HFind the percent overshoot, settling time, rise time, and peak time for 14.145 T (s) = (s2 +0.824s+2.892) (s+5)
- Questions 16 to 20 (Write True or False) A16 A larger inductor produces a smaller rate of change of current. A17 KVL states that E IR + E EMF = 0 for any open circuits. A18 For a sine waveform, the value of form factor is 1.414. A19 In a purely inductive circuit, the current lags the voltage by II/4 rads. In an ideal transformer, the rate of change of flux is the same for both primary A20 and secondary.1) The switch in the ciruit, shown in belou has been in Posikon "a" for a long hime. At t=0, the switch moves instantancously ho positron "b". Find volt) for t70 960n 1602 o.SmH 28V 12-5 nF 20v Volt)In the figure: R1 = 1439.170, R2 = R1 and R3 =2R2, then determine the value of the voltage source E. a 8 mA 10 mA 2 mA RT R1 R2 R3 O 25.33 11.51 O 17.27 15.43 13.82 +