Given a list of integers, we want to know whether it is possible to choose a subset of some of the integers, such that the integers in the subset adds up to the given sum recursively. We also want that if an integer is chosen to be in the sum, the integer next to it in the list must be skipped and not chosen to be in the sum. Do not use any loops or regular expressions. Test cases: skipSum( [2, 5, 10, 6], 12) true skipSum( [2, 5, 10, 6], 7) false skipSum( [2, 5, 10, 6], 16) false Given code: public static boolean skipSum(List list, int sum) { // call your recursive helper method return skipSumHelper (list, 0, sum); } 1. 2. 3. 4. For example: Test Result List list = Arrays.aslist(2, 5, 10, 6); true int sum = 12; System.out.println(skipSum(list, sum)); List list Arrays.asList(2, 5, 10, 6); false = int sum = 7; System.out.println(skipSum(list, sum)); List list = Arrays.aslist(2, 5, 10, 6); false int sum = 16; System.out.println(skipSum(1ist, sum));

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter15: Recursion
Section: Chapter Questions
Problem 6PE
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Complete this code

Do not use any loops or regular expressions.
THIS IS THE GIVEN CODE

public static boolean skipSum(List<Integer> list, int sum) {
// call your recursive helper method
returnskipSumHelper(list, 0, sum);
}


private static boolean skipSumHelper(List<Integer> list, int start, int sum) {
    // base case

    // recursive step

}
Given a list of integers, we want to know whether it is possible to choose a
subset of some of the integers, such that the integers in the subset adds up to
the given sum recursively.
We also want that if an integer is chosen to be in the sum, the integer next to it in
the list must be skipped and not chosen to be in the sum.
Do not use any loops or regular expressions.
Test cases:
skipSum([2, 5, 10, 6], 12)
true
skipSum([2, 5, 10, 6], 7)
false
skipSum([2, 5, 10, 6], 16)
false
Given code:
public static boolean skipSum (List<Integer> list, int sum) {
// call your recursive helper method
return skipSumHelper (list, e, sum);
1.
2.
3.
4.
For example:
Test
Result
List<Integer> list
Arrays.asList(2, 5, 10, 6); true
int sum = 12;
System.out.println(skipSum(list, sum));
List<Integer> list = Arrays.aslist(2, 5, 10, 6); false
int sum = 7;
System.out.println(skipSum(list, sum));
List<Integer> list
Arrays.aslist(2, 5, 10, 6); false
int sum =
16;
System.out.println(skipSum(1list, sum));
Transcribed Image Text:Given a list of integers, we want to know whether it is possible to choose a subset of some of the integers, such that the integers in the subset adds up to the given sum recursively. We also want that if an integer is chosen to be in the sum, the integer next to it in the list must be skipped and not chosen to be in the sum. Do not use any loops or regular expressions. Test cases: skipSum([2, 5, 10, 6], 12) true skipSum([2, 5, 10, 6], 7) false skipSum([2, 5, 10, 6], 16) false Given code: public static boolean skipSum (List<Integer> list, int sum) { // call your recursive helper method return skipSumHelper (list, e, sum); 1. 2. 3. 4. For example: Test Result List<Integer> list Arrays.asList(2, 5, 10, 6); true int sum = 12; System.out.println(skipSum(list, sum)); List<Integer> list = Arrays.aslist(2, 5, 10, 6); false int sum = 7; System.out.println(skipSum(list, sum)); List<Integer> list Arrays.aslist(2, 5, 10, 6); false int sum = 16; System.out.println(skipSum(1list, sum));
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