Given a binary tree, write a function that prints the binary search tree’s nodes level by level, for example the following tree will have the following output statement: 1, 2, 3, 4, 5
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Given a binary tree, write a function that prints the binary search tree’s nodes level by level, for example the following tree will have the following output statement:
1, 2, 3, 4, 5
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- #ifndef LLCP_INT_H#define LLCP_INT_H #include <iostream> struct Node{ int data; Node *link;};void DelOddCopEven(Node*& headPtr);int FindListLength(Node* headPtr);bool IsSortedUp(Node* headPtr);void InsertAsHead(Node*& headPtr, int value);void InsertAsTail(Node*& headPtr, int value);void InsertSortedUp(Node*& headPtr, int value);bool DelFirstTargetNode(Node*& headPtr, int target);bool DelNodeBefore1stMatch(Node*& headPtr, int target);void ShowAll(std::ostream& outs, Node* headPtr);void FindMinMax(Node* headPtr, int& minValue, int& maxValue);double FindAverage(Node* headPtr);void ListClear(Node*& headPtr, int noMsg = 0); // prototype of DelOddCopEven of Assignment 5 Part 1 #endifclass Node { int key; Node l, r; public Node(int item) { key = item; l = r = null; }} class Main{ Node root; Main() { root = null; } void Postorder(Node node) { if (node == null) return; Postorder(node.l); Postorder(node.r); System.out.print(node.key + " "); } void Inorder(Node node) { if (node == null) return; Inorder(node.l); System.out.print(node.key + " "); Inorder(node.r); } void Preorder(Node node) { if (node == null) return; System.out.print(node.key + " "); Preorder(node.l); Preorder(node.r); } void Postorder() { Postorder(root); } void Inorder() { Inorder(root); } void Preorder() { Preorder(root); } public static void main(String[] args) { Main tree = new Main(); tree.root = new Node(27); tree.root.l =…class Polynomial: class TermNode:def __init__(self, coefficient: int, exponent: int) -> None:"""Initialize this node to represent a polynomial term with thegiven coefficient and exponent. Raise ValueError if the coefficent is 0 or if the exponentis negative."""if coefficient == 0:raise ValueError("TermNode: zero coefficient")if exponent < 0:raise ValueError("TermNode: negative exponent") self.coeff = coefficientself.exp = exponentself.next = None def __init__(self, coefficient: int = None, exponent: int = 0) -> None:"""Initialize this Polynomial with a single term constructed from thecoefficient and exponent. If one argument is given, the term is a constant coefficient(the exponent is 0).If no arguments are given, the Polynomial has no terms. # Polynomial with no terms:>>> p = Polynomial()>>> print(p._head)None>>> print(p._tail)None # Polynomial with one term (a constant):>>> p = Polynomial(12)>>> p._head.coeff12>>>…
- Student Name: 8) Consider the following ciass definitions. public class LibraryID{ private String name; // Person's name private int ID; // Person's library ID # private ArrayList Books; // Loaned books public LibraryID (String n, int num) { name = n; ID = num; Books = new ArrayList(); } public int getID () { return ID; } public String getName() { return name; } /* CheckOut () and ReturnBook () methods not shown */ Complete the following override method, contained in the LibraryID class. Two LibraryID's are considered the same if their ID numbers are the same. public boolean equals (Object other) { if (other == null){ return false;} LibraryID o = (LibraryID) other; 9) Assuming the code written in 8 is correct, write the call to compare LibraryID one and two inside the if statement. LibraryID one = new LibraryID("Mankind", 106); LibraryID two = new LibraryID ("Mick Foley", 106); if System.out.println("ID's belong to the same person"); else System.out.println("ID's belong to the…#include using namespace std; struct ListNode { string data; ListNode *next; }; int main() { ListNode *p, *list; list = new ListNode; list->data = "New York"; p new ListNode; p->data = "Boston"; list->next = p; p->next = new ListNode; p->next->data = "Houston"; p->next->next = nullptr; // new code goes here Which of the following code correctly deletes the node with value "Boston" from the list when added at point of insertion indicated above? O list->next = p; delete p; O p = list->next; %3D list->next = p->next; delete p; p = list->next; list = p->next; delete p; O None of these O p = list->next; %3D list->next = p; %3D delete p;design patterns quetion public double calculatePerimeter(Shapes [] shapes) { double p = 0;for (Shape shape : shapes) { if (shape is Rectangle) { Rectangle rectangle = (Rectangle) shape; p += (rectangle.Width+rectangle.Height) * 2; } else { Circle circle = (Circle)shape; p += 2 * circle.Radius * Math.PI; } } return p; } which design principle is violated in the above code? what is the issue/ limitation of this code? rewrite the code to not violate the design principle you answered in part 1?
- class Artist{StringsArtist(const std::string& name="",int age=0):name_(name),age_(age){}std::string name()const {return name_;}void set_name(const std::string& name){name_=name;}int age()const {return age_;}void set_age(int age){age_=age;}virtual std::string perform(){return std::string("");}private:int age_;std::string name_;};class Singer : public Artist{public:Singer():Artist(){};Singer(const std::string& name,int age,int hits);int hits() const{return hits_;}void set_hits(int hit);std::string perform();int operator+(const Singer& rhs);int changeme(std::string name,int age,int hits);Singer combine(const Singer& rhs);private:int hits_=0;};int FindOldestandMostSuccess(std::vector<Singer> list); Task: Implement the function int Singer::changeme(std::string name,int age,int hits) : This function should check if the values passed by name, age and hits are different than those stored. And if this is the case it should change the values. This should be done by…class Artist{StringsArtist(const std::string& name="",int age=0):name_(name),age_(age){}std::string name()const {return name_;}void set_name(const std::string& name){name_=name;}int age()const {return age_;}void set_age(int age){age_=age;}virtual std::string perform(){return std::string("");}private:int age_;std::string name_;};class Singer : public Artist{public:Singer():Artist(){};Singer(const std::string& name,int age,int hits);int hits() const{return hits_;}void set_hits(int hit);std::string perform();int operator+(const Singer& rhs);int changeme(std::string name,int age,int hits);Singer combine(const Singer& rhs);private:int hits_=0;};int FindOldestandMostSuccess(std::vector<Singer> list); Implement the function Singer Singer::combine(const Singer& rhs):It should create a new Singer object, by calling the constructor with the following values: For name it should pass a combination of be the name of the calling object followed by a '+' and then…Part 2: Create the following struct: struct nodeType { Point value; nodeType * Link; };#ifndef PLAYER_H#define PLAYER_Hclass Player{private:string name;int score;public:void setName(string na);void setScore(int sc);int getScore();string getName();};#endif#include <iostream>using namespace std; class TurtleNode { public: TurtleNode(int babiesInit = 0, TurtleNode* nextLoc = nullptr); void InsertAfter(TurtleNode* nodeLoc); TurtleNode* GetNext(); void PrintNodeData(); private: int babiesVal; TurtleNode* nextNodePtr;}; TurtleNode::TurtleNode(int babiesInit, TurtleNode* nextLoc) { this->babiesVal = babiesInit; this->nextNodePtr = nextLoc;} void TurtleNode::InsertAfter(TurtleNode* nodeLoc) { TurtleNode* tmpNext = nullptr; tmpNext = this->nextNodePtr; this->nextNodePtr = nodeLoc; nodeLoc->nextNodePtr = tmpNext;} TurtleNode* TurtleNode::GetNext() { return this->nextNodePtr;} void TurtleNode::PrintNodeData() { cout << this->babiesVal << endl;} int main() { TurtleNode* headObj = nullptr; TurtleNode* firstTurtle = nullptr; TurtleNode* secondTurtle = nullptr; TurtleNode* currTurtle = nullptr; int babies1; int babies2; cin >> babies1; cin…SEE MORE QUESTIONS