Give the margin of error for the 90% confidence interval for µd = µ1 – H2
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- Concentration of atmospheric pollutants such as carbon monoxide (CO) can be measured with a spectrophotometer. In a calibration test, 50 measurements were taken of laboratory gas sample that is known to have a CO concentration of 70 ppm. A measurement is considered to be satisfactory if it is within 5 ppm of the true concentration. Of the 50 measurements, 37 were satisfactory. Find a 95 % confidence interval for the proportion of measurements made by this instrument that will be satisfactory. How many measurements must be taken to specify the proportion of satisfactory measurements to within+0.10 with 95% confidence?We suspect that Method 1 for detecting impurities in iron ingots yields higher results than Method 2 for finding such impurities. We want to give a 95% confidence interval for the difference in the average number of impurities detected by the two methods. In order to obtain the confidence interval, we measured the impurities of 3 ingots, employing both methods for each ingot. The results are presented in the table below. We let 1 denote the population average number of defects for Method 1 and 2 denotes the population average number of defects for Method 2. We wish to develop a confidence interval for ??=?1−?2μd=μ1−μ2 Give the margin of error for the 95% confidence interval for ??=?1−?2μd=μ1−μ2 Ingot 1 Ingot 2 Ingot 3 Method 1 16 32 12 Method 2 12 26 10The melting points of two alloys used in formulating solder were investigated by melting 21 samples of each material. The sample mean and standard deviation for alloy 1 was īi = 420°F and si = T2 = 426°F and s2 = 3°F. Find a 95% confidence interval on the difference in 4°F , and for alloy 2, they were %3D the two means. (-0.061, 0.861) -4.119, 15.129) (-8.205, –3.795) (1.857, 18.943)
- Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From process 1, the sample size was 10 and had a mean and standard deviation of 180 and 15, respectively. From process 2, the sample size was 4 with a mean and standard deviation of 360 and 50, respectively. X Your answer is incorrect. Find a 95% confidence interval on the difference in the towels' mean absorbency produced by the two processes. Assume the standard deviations are estimated from the data. Round your answers to two decimal places (e.g. 98.76).A confidence interval is desired for the true mean stray-load loss (Watts) for a certain type of induction motor. Assume that the stray-load loss is normally distributed with =3.3Watts. You take 25 measurements of stray-load loss from induction motors and determine that the mean of your sample is 53.6 Watts. Given the information in this first situation, what equation for the interval estimate endpoints will you need to use for this problem? Also, why did you choose that equation? (In other words, what assumptions can you make?) Compute a 95% confidence interval for this situation.A 95% confidence interval for the mean was computed with a sample of size 90 to be (16,22). Then the Error is ±3.A biology student measured the ear lengths of an SRS of 10 Mountain cottontail rabbits, and an SRS of 10 Holland lop rabbits. The ear lengths for the two samples are listed in the two tables attached (see attached image). (a) Calculate a 95% confidence interval for the difference in mean ear lengths between Mountain cottontail rabbits and Holland lop rabbits. Make sure to define which is “µ1” and which is “µ2.” (You can complete the calculations either by hand or using R, but remember to show all your work.) (b) Do Holland lop rabbits have longer ears on average than Mountain cottontail rabbits? Carry out a test of significance to answer this question. Show your work at each step. Don’t forget to state the hypotheses at the start (making sure to define all parameters), and to include a conclusion in terms of the original problem. (You can complete the calculations either by hand or using R, but remember to show all your work.)Let us suppose we have data on the absorbency of paper towels that were produced by two different manufacturing processes. From process 1, the sample size was 10 and had a mean and standard deviation of 190 and 15, respectively. From process 2, the sample size was 4 with a mean and standard deviation of 350 and 50, respectively. Find a 95% confidence interval on the difference in the towels' mean absorbency produced by the two processes. Assume the standard deviations are estimated from the data. Round your answers to two decimal places (e.g. 98.76). eTextbook and Media How would you interpret this CI? O The hypothesis test for the equality of means would not reject the null hypothesis (that the means do not differ) at a = 0.05. O The hypothesis test for the equality of means would reject the null hypothesis (that the means do not differ) at a = 0.05. eTextbook and Media Is the value zero in the Cl? O Yes, zero is contained in this interval. O No, zero is not contained in this…A 95% two-sided confidence interval for μ which has been calculated using R turns out to be (0, 1). A 90% two-sided confidence interval based on the same data will contain the value 0.9 (True, cannot tell, or False)If we want a 96% confidence interval on population mean with a sample size of 23, find zα2 or tα2A 95% confidence interval for the mean was computed with a sample of size 100 to be (10,14). Then the Error is ±2. true or falseUnfortunately, arsenic occurs naturally in some ground water. A mean arsenic level of µ = 8 parts per billion (ppb) is considered safe for agricultural use. A well in Los Banos is used to water cotton crops. This well is tested on a regular basis for arsenic. A random sample of 37 tests gave a sample mean of = 7.3ppb arsenic. It is known that o = 1.9ppb for this type of data. Does this information indicate that the mean level of arsenic in this well is less than 8 ppb? Use the classical approach. Use a = 0.01 What is the calculation (step 4) for this problem? Z = -2.34 z = 2.34 z = 2.24 z = -2.24SEE MORE QUESTIONS