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- What does an EXCEPT (MINUS) query care about operand order, while a UNION query doesn't?Salesforce Problem: Design a SOQL query to fetch all the profile who have access to read the object records.Using Salesforce Only: Write a SOQL query on account object and try to get the 5 fields value which include name of the account and arrange it in descending order of name.
- Develop a PL/SQL block that would go through all the employees from EMPLOYEES table who work in department id= 90 (there is suppose to be 3 employee who work in Department 90)- IN BEGIN END END SECTION; Execute 3 separate of SELECT statement one after the other. Each SELECT will pull first name. salary of each employee and store them in local variables.+ SELECT LOAD INTO v_firstname1, v_salarxlWHERE emrlexee.id=100 Then second WHERE emploxee.id3101+ SELECT first_name, salary INTO v_firstname2, v_salary2 Then third + SELECTSELECTI tirst.name, salary INTO v_firstname3, v_salary3 iin WHERE emploxee id=102 ..... You must now have 6 local variables. DECLARE all of them accordingly in DECLARE section and use them in BEGIN and END.+ Then add another SELECT statement in BEGIN-END to find company average salary SELECT xa(salary) INTO aKasal FROM EMPLOYEES; !!! Do not forget to create y avgsal local variable in DECLARE section.Write query of it.1. Create a PL/SQL function. The minimal requirements: using the cursor in PLSQL function, retrieve data from object table and record the data in the PL/SQL table, make calculations with object data and define return value of the function, test the operation of the function (get the result). The maximal requirements: you can add IF-ELSEIF's, cursor processing in loops, more interesting semantic functions. 2. Create methods for object types. The minimal requirements: use map/order methods (1 method) (method+ demonstration), use MEMBER methods (2 methods) (methods + demonstration). The maximal requirements: non-trivial methods, that use more complex comparisons or do more complex calculations – i.e., give a couple more constructs in code. 3. Demonstrate the multiset operators. The minimal requirements: using 2 different multiset operators (can be included in the code), they can also be used in the The maximal requirements: the queries make sense semantically, one of the queries is a…
- SQL: Create a SQL query that uses an uncorrelated subquery and no joins to display the descriptions for products provided by a vendor in area code 615. Remember, the main difference between a correlated subquery and uncorrelated subquery is that, in a correlated subquery, the inner query is dependent upon the outer query, while, with an uncorrelated query, the inner query does not depend upon the outer query. Instead, it runs just once. You should NOT use union, minus, or intersect in this query. The outer query will use the PRODUCT table and the inner query will use the VENDOR table [hint: you should have 9 records of output]. My code: select p_descript from product where (select v_areacode from vendor where v_areacode = '615' ; I am getting this error, problem is I can't see what is missing any assistance is appreciated. ORA-00936: missing expression2. Get the Groups As new students begin to arrive at college, each receives a unique ID number, 1 to n. Initially, the students do not know one another, and each has a different circle of friends. As the semester progresses, other groups of friends begin to form randomly. There will be three arrays, each aligned by an index. The first array will contain a queryType which will be either Friend or Total. The next two arrays, students1 and students2, will each contain a student ID. If the query type is Friend, the two students become friends. If the query type is Total, report the sum of the sizes of each group of friends for the two students.For MySQL Import the data in the Types.txt into the BOOK_TYPE table.
- Let's wa(k through a review of basic SQL syntax, using as an example the database that was mentionedearlier. This database has the following simple structure(* indicates a primary key):Courses: CourseID*, CourseName, TeacherIDTeachers: TeacherID*, TeacherNameStudents; StudentID*, StudentNameStudentCourses: CourseID*, StudentID*Using the above table, implement the following queries.Query 1: Student Enrollment Query 2: Teacher Class SizeBuilding #11 is undergoing a major renovation. Implement a query to close allrequests from apartments in this building.If you're using MySQL, import the information from Types.txt into the BOOK TYPE database.