For the given figure, v. = 38/38°V. Find the average power absorber by the 100 resistor. 492 -j502 ww and 0.1V V. 810 j5Q2 10 22 The average power absorber by the 100 resistor is Vo kW (Calculate to 2 decimal places)

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...
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For the given figure, vg = 38/38°V. Find the average power absorber by the 100 resistor.
-j5 Q
4Ω
v. (±) 0.1Vo
S
810
j5 22 1022
The average power absorber by the 100 resistor is
www
kW (Calculate to 2 decimal places)
Transcribed Image Text:For the given figure, vg = 38/38°V. Find the average power absorber by the 100 resistor. -j5 Q 4Ω v. (±) 0.1Vo S 810 j5 22 1022 The average power absorber by the 100 resistor is www kW (Calculate to 2 decimal places)
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