For the following processes, estimate average waiting time for priotiry scheduling combines with round robin scenario.Consiider quanta of 1s. Process Burst TimePriority P1 10 3 P2 1 1 P3 2 P4 1 Ps 2 P6 6.
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- Suppose there are N worker processes defined as follows. Develop a monitor BarrierSyn with a procedure passBarrier() for barrier synchronization. Use the Signal and Continue discipline. Hint: In the monitor BarrierSyn, you may define a condition variable oktopass and use signal_all(oktopass) primitive to wait up all delayed processes on the condition variable. process Worker[i = 1 to N] { while (true) { code to implement task i; BarrierSyn.passBarrier(); } }Suppose that an operating system supports two kinds of sequential processes: high-priority interactive processes, and low-priority non-interactive processes. The behavior of the high-priority processes is to alternate between periods of computation of duration Tc and periods of blocking (waiting for input) of duration Tb. The behavior of the low-priority processes is to compute constantly, with no blocking. The operating system’s scheduling policy is round-robin with a quantum q, where Tc < q. Scheduling decisions are made only when a quantum expires, or when the running process blocks. The scheduler selects a low-priority process to run only if no high-priority processes are ready. Suppose there is one high-priority process and one low-priority process in the system, and that both processes will run for a long time. For what fraction of the time does the low-priority process run?An interactive system using round-robin scheduling and swapping tries to giveguaranteed response to trivial requests as follows: After completing a round robin cycleamong all ready processes, the system determines the time slice to allocate to eachready process for the next cycle by dividing a maximum response time by the number ofprocesses requiring service. Is this a reasonable policy?
- Given the list of processes, their CPU burst times, arrival times and priorities implement SJF,Priority and Round Robin scheduling algorithms on the processes with preemption. For each ofthe scheduling policies, compute and print the completion Time(CT), Turnaround Time(TAT),and Waiting Time(WT) for each process using C Programming.Waiting time: Processes need to wait in the process queue before execution starts and inexecution while they get preempted. Turnaround time: Time elapsed by each process to get completely served. (Difference betweensubmission time and completion time).Folowing are the given Process, Arrival time and burst time. Process Arrival time Burst time P1 8 1 P2 5 1 P3 2 7 P4 4 3 P5 2 8 P6 4 2 P7 3 5 You'll have to draw two Gantt charts illustrating the execution of these processes using SJF-non-preemptive and SJF-preemptive scheduling algorithm. Also draw Gantt Chart of RR with Time Quantum of 2. and calculate Average waiting time and which of the schedules above results in the minimal average waiting time (over all processes)?We define an m-section to be a sequence of code that can be run concurrently by maximum m threads. There are n threads in a process. Each thread executes a thread function doWork() that calls doCriticalWork() in an infinite loop. Function doCriticalWork() requires that at most m threads run it concurrently. The enter() and leave() functions are used to limit the number of threads within the m- section to a maximum of m and are the only functions that deal with synchronization. The pseudo-code algorithm for the thread function is this: void doWork(...) { while (true) { enter(...); I/ limit access to m threads Il execute m-section doCriticalWork(.); Il run by max. m threads leave(.); I/ leave m-section Il do more work Function enter() returns immediately only if there are less than m threads in the m-section. Otherwise, the calling thread will be blocked. A thread calls leave() to indicate it has finished the m-section. If there was another thread blocked (in enter() waiting to enter the…
- Consider a job mix in which there is one CPU-intensive job, A, that has a single infinitely long CPU burst, and 3 I/O-intensive jobs, B, C, and D. The scheduler uses Round Robin scheduling with a time quantum of 3 ms. Here is an observed execution, where initially A is running and B, C, and D are in the ready queue in this order: AAAoBBoCoDoAAAoBBoAAAoDoAAAoBBoCoDoAAAoBBo Answer the following questions based on the above. Explain and give a specify a part of the execution. a) Could any of B’s I/O-burst time be 6 ms? Explain. b) Could any of B’s I/O-burst time be 4 ms? Explain.An Ice-cream factory is up for some production work. They have certain jobs to take up. The jobs have job ids J1, J2, J3 and J4. The jobs from J1 to J4 arrive in the time interval of 0, 3, 5, and 7 with the burst time as 8, 2, 6 and 3 respectively. The time quantum is provided as 2 and the factory performs a Round Robin Scheduling to schedule the jobs. Considering all these parameters, compute the following a) Design a Gantt chart for illustrating the execution of these jobs. b) Calculate the average turnaround time and the response time."Semaphore' is a synchronization tool used to solve the critical section problem. Various types of errors can be generated when semaphores are used incorrectly. Suppose that 2 concurrent processes, P, and P,, are cooperating using the wait() and the signal() operations over the 'sem' semaphore. Below, on the left side, there is the pseudo-code of a correct process Pj. Which type of danger generates the incorrect process P; when running in parallel with P;? Make a simulation to justify your answer (no point without a valid simulation). Pseudo-code P; | Pseudo-code P; wait (sem); critical section; wait(sem); critical section; wait(sem) signal(sem);
- Consider a system consisting of m resources of the same type being shared by n processes, n > m. Each process has a maximum need of m/2 resources. Initially, each process has no resource requests. A process can request or release only one resource at a time. With n=3k and m=2k, for some integer k, show that the system is deadlock free.Process Arrival time Priority Burst time P1 8 P2 1 6. P3 9 P4 8 2 10 P5 3 2 Now, Calculate the avarage watiting time, avarage turnaround time and execution starting time for specific processes using Preemtive Priority scheduling algorithm, where A higher value represents Higer Priority. Insert the Execution Starting Time of Process P2 (only integer value, no decilam points. For example if your ans is 26.8 or 26.1, insert 26 only) Insert the Execution Starting Time of Process P3 (only integer value, no decilam points. For example if your ans is 26.8 or 26.1, insert 26 only) Insert the Execution Starting Time of Process P5 (only integer value, no decilam points. For example if your ans is 26.8 or 26.1, insert 26 only)A job scheduler gets work requests with a priority of execution attached to it, in the following sequence. The higher the priority value, the more important task execution.Work ID: 464 212 110 840 976 3433 2 3 1 2 2 Priority: 3 2 3 1 2 2Create a treap for the jobs that are set to run. What will the treap look like after the highest priority jobs have finished execution and thus left the treap?