For question number 4 part b is the anode: Mg2+(aq) or Mg (s)? And is the cathode Ag+(aq) or Ag (s)? By the way I got 3.17 V for part A if that helps. Thanks!

Chemistry: Principles and Practice
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Chapter18: Electrochemistry
Section: Chapter Questions
Problem 18.59QE
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For question number 4 part b is the anode: Mg2+(aq) or Mg (s)? And is the cathode Ag+(aq) or Ag (s)? By the way I got 3.17 V for part A if that helps. Thanks!
TABLE 18.1 Standard Electrode Potentlals at 25 °C
Reduction Half-Reaction
F) + 2 e
E (V)
+ 2F (aq)
Stronger
oxidizing agent H202(aq) + 2 H*(aq) + 2 e
2.87
+2 H20(0
→ PBSO«(s) + 2 H20(1)
→ Mn02(s) + 2 H20()
- Mn*(aq) + 4 H20(1)
Weaker
reducing agent
PbO2(s) + 4 H*(ag) + SO,²¯(aq) + 2 e
Mn04 (aq) + 4 H*(aq) + 3 e
Mno. (aq) + 8 H*(aq) + 5 e
Au+(aq) + 3e
Pb02(s) + 4 H*(aq) + 2 e
1.78
1.69
1.68
1.51
- Au(s)
1.50
- Pb2*(aq) + 2 H20()
→ 2 cr (aq)
2 C*(aq) + 7 H2O)
2 H20(1)
Mn+(aq) + 2 H,01)
+ (aq) + 3 H20()
1.46
Cl2lg) + 2 e
Cr30, (aq) + 14 H*(aq) + 6 e
02(g) + 4 H*(aq) + 4 e
MnO2(s) + 4 H*(aq) + 2 e
10, (aq) + 6 H*(aq) + 5 e
Br() + 2 e
Vo,"(aq) + 2 H*(aq) + e
NO, (aq) + 4 H*(aq) + 3 e-
1.36
1.33
→
1.23
1.21
1.20
→
2 Br (aq)
1.09
- vo?"(aq) + H20()
NOE) + 2 H20(1)
→ CIO, (aq)
1.00
0.96
CIO2() + e
Ag"(aq) + e
Fe*(aq) + e
0.95
Ag(s)
+ Fe?*(aq)
0.80
0.77
02(g) + 2 H*(aq) + 2 e
Mno, (aq) +e
b(s) + 2 e
Cu*(aq) + e
+H2O2(aq)
0.70
→ Mn0,2 (aq)
→21 (aq)
→ Cu(s)
4 OH (aq)
+ Cu(s)
→ H2SO3(aq) + H20(1)
- Cu*(aq)
- Sn*(aq)
0.56
0.54
0.52
02g) + 2 H20(1) + 4 e
Cu*(aq) + 2 e
0.40
0.34
so, (aq) + 4 H*(aq) + 2 e
Cu2*(aq) + e
Snt(aq) + 2 e
2 H*(aq) + 2 e
Fe(aq) + 3 e
0.20
0.16
0.15
- H2g)
→ Fe(s)
→ Pb(s)
→ Sn(s)
-0.036
Pb2 (aq) + 2 e
Sn2+(aq) + 2 e
N2*(aq) + 2 e
Cd*(aq) + 2 e
Fe2+(aq) + 2 e
Cr*(aq) + e
Cr (aq) + 3 e
Zn*(aq) + 2 e
-0.13
-0.14
Ni(s)
-0.23
→ Cd(s)
-0.40
- Fe(s)
Cr2*(aq)
-0.45
-0.50
- Cr(s)
-0.73
+ Zn(s)
-0.76
+ H2g) + 2 OH (aq)
→ Mn(s)
+ Al(s)
-0.83
2 H20() + 2 e
Mn2 (aq) + 2 e
-1.18
-1.66
A*(aq) + 3 e
Mg2+(aq) + 2 e
Na (aq) + e
Ca (aq) + 2 e
Ba?+(aq) + 2 e
K*(aq) + e
oxidizing agent u*(aq) + e¯
-2.37
→ Mg(s)
→ Na(s)
-2.71
- Ca(s)
-2.76
- Ba(s)
-2.90
Stronger
reducing agent
- K(s)
-2.92
Weaker
- U(s)
-3.04
Transcribed Image Text:TABLE 18.1 Standard Electrode Potentlals at 25 °C Reduction Half-Reaction F) + 2 e E (V) + 2F (aq) Stronger oxidizing agent H202(aq) + 2 H*(aq) + 2 e 2.87 +2 H20(0 → PBSO«(s) + 2 H20(1) → Mn02(s) + 2 H20() - Mn*(aq) + 4 H20(1) Weaker reducing agent PbO2(s) + 4 H*(ag) + SO,²¯(aq) + 2 e Mn04 (aq) + 4 H*(aq) + 3 e Mno. (aq) + 8 H*(aq) + 5 e Au+(aq) + 3e Pb02(s) + 4 H*(aq) + 2 e 1.78 1.69 1.68 1.51 - Au(s) 1.50 - Pb2*(aq) + 2 H20() → 2 cr (aq) 2 C*(aq) + 7 H2O) 2 H20(1) Mn+(aq) + 2 H,01) + (aq) + 3 H20() 1.46 Cl2lg) + 2 e Cr30, (aq) + 14 H*(aq) + 6 e 02(g) + 4 H*(aq) + 4 e MnO2(s) + 4 H*(aq) + 2 e 10, (aq) + 6 H*(aq) + 5 e Br() + 2 e Vo,"(aq) + 2 H*(aq) + e NO, (aq) + 4 H*(aq) + 3 e- 1.36 1.33 → 1.23 1.21 1.20 → 2 Br (aq) 1.09 - vo?"(aq) + H20() NOE) + 2 H20(1) → CIO, (aq) 1.00 0.96 CIO2() + e Ag"(aq) + e Fe*(aq) + e 0.95 Ag(s) + Fe?*(aq) 0.80 0.77 02(g) + 2 H*(aq) + 2 e Mno, (aq) +e b(s) + 2 e Cu*(aq) + e +H2O2(aq) 0.70 → Mn0,2 (aq) →21 (aq) → Cu(s) 4 OH (aq) + Cu(s) → H2SO3(aq) + H20(1) - Cu*(aq) - Sn*(aq) 0.56 0.54 0.52 02g) + 2 H20(1) + 4 e Cu*(aq) + 2 e 0.40 0.34 so, (aq) + 4 H*(aq) + 2 e Cu2*(aq) + e Snt(aq) + 2 e 2 H*(aq) + 2 e Fe(aq) + 3 e 0.20 0.16 0.15 - H2g) → Fe(s) → Pb(s) → Sn(s) -0.036 Pb2 (aq) + 2 e Sn2+(aq) + 2 e N2*(aq) + 2 e Cd*(aq) + 2 e Fe2+(aq) + 2 e Cr*(aq) + e Cr (aq) + 3 e Zn*(aq) + 2 e -0.13 -0.14 Ni(s) -0.23 → Cd(s) -0.40 - Fe(s) Cr2*(aq) -0.45 -0.50 - Cr(s) -0.73 + Zn(s) -0.76 + H2g) + 2 OH (aq) → Mn(s) + Al(s) -0.83 2 H20() + 2 e Mn2 (aq) + 2 e -1.18 -1.66 A*(aq) + 3 e Mg2+(aq) + 2 e Na (aq) + e Ca (aq) + 2 e Ba?+(aq) + 2 e K*(aq) + e oxidizing agent u*(aq) + e¯ -2.37 → Mg(s) → Na(s) -2.71 - Ca(s) -2.76 - Ba(s) -2.90 Stronger reducing agent - K(s) -2.92 Weaker - U(s) -3.04
4) Please consider the following galvanic cell setup: the cell is composed of a silver rod dipped
into a silver nitrate solution connected (via a salt bridge) to a solution of a magnesium rod dipped
into a magnesium chloride solution.
(a) Calculate the standard cell potential.
(b) Define the anode and cathode.
5) A major source of sodium metal is the electrolysis of molten sodium chloride. What magnitude
of current produces 1.0 kg of sodium metal in 1 hour? (M for Na =23.0g/mol).
Transcribed Image Text:4) Please consider the following galvanic cell setup: the cell is composed of a silver rod dipped into a silver nitrate solution connected (via a salt bridge) to a solution of a magnesium rod dipped into a magnesium chloride solution. (a) Calculate the standard cell potential. (b) Define the anode and cathode. 5) A major source of sodium metal is the electrolysis of molten sodium chloride. What magnitude of current produces 1.0 kg of sodium metal in 1 hour? (M for Na =23.0g/mol).
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