For a projectile lunched with an initial velocity of vo at an angle of 8 (between O and 90°), a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of e gives the highest maximum height?
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- For a projectile lunched with an initial velocity of vo at an angle of 0 (between 0 and 90°), a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of 0 gives the highest maximum height? Solution The components of vo are expressed as follows: Vinitial-x = Vocos(e) Vinitial-y = vosin(e) a) Let us first find the time it takes for the projectile to reach the maximum height. Using: Vfinal-y = Vinitial-y * ayt since the y-axis velocity of the projectile at the maximum height is Vfinal-y= Then, = Vinitial-y + ayt Substituting the expression of Vịnitial-y and ay = -g, results to the following: Thus, the time to reach the maximum height is tmax-height= We will use this time to the equation Yfinal - Yinitial = Vinitial-yt + (1/2)ayt2 if we use the time reach the maximum height, therefore, the displacement will yield the hum height, so hmax = Vinitial-yt + (1/2)ayt2 substituting, the vinitial-y expression above, results to the following hmax = t+…Problem For a projectile lunched with an initial velocity of vo at an angle of 0 (between 0 and 90°), a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of e gives the highest maximum height? Solution The components of vo are expressed as follows: Vinitial-x = Vocos(0) Vinitial-y = Vosin(e) a) Let us first find the time it takes for the projectile to reach the maximum height. Using: Vfinal-y = Vinitial-y + ayt since the y-axis velocity of the projectile at the maximum height is Vfinal-y %3D Then, Vinitial-y + ayt Substituting the expression of vinitial-y and ay = -g, results to the following: t Thus, the time to reach the maximum height is tmax-height = We will use this time to the equation Yfinal - Yinitial = Vinitial-yt + (1/2)ayt if we use the time taken to reach the maximum height, therefore, the displacement will yield the maximum height, so hmax = Vinitial-yt + (1/2)ay? substituting, the vinitial-y expression above, results to…The figure shows the path taken by a drunk skunk over level ground, from initial point i to final pointL The angles are 6 - 30.0o: - 51.0 and - 77.0.and the distances are dy - 440 m d - 7.10m and dy - 13.0m What are the ta) magnitude and Ibi angle of the skunk's displacement fromi to Give the ande as a positive (counterdlockwisel or negative (clockwise) angle of magnitude less than 180 measured from the direction la) Number Units (b) Number Units
- A Canada goose flew 1.45 km [15.0 ̊ S of W] to feed, then it flew 1.64 km [70.0 ̊ S ofE] to its roosting location. Determine the goose’s displacement, using thegraphical/tip-to-tail method of vector addition. Answer to two significant digits.Question 4: A particle is thrown into air with initial speed vo making angle 0 with the horizontal as shown in Figure 1. The gravitational acceleration g and a constant acceleration a, due to a wind act on the particle. Find the range of the motion. a, 'w Figure 1 100sin(20) where vo is the initial velocity in feet per second and is the angle of elevation. If yo 2300 feet per second and is changed from 13° to 14° use differentials to approximate the change in the range. Round your answer to the nearest integer. The range R of a projectile is R = Select one: Ⓒa. 2811 ft X b. 2593 ft C. 5623 ft d. 4568 ft 5186 ft e. = Incorrect 32
- The world long jump record is 8.95 m (Mike Powell, USA,1991). Treated as a projectile, what is the maximum rangeobtainable by a person if he has a take-off speed of 9.5 m/s?State your assumptionsdsOne morning, Cosdnnie walks from her house to go to a store that is 500 ft, S 40o W from her hdouse. She starts walking 120 ft, SW; then continues walking 100 ft, 10o S of E; then sees a friend who is 700 ft, 30o N of E from where she isdasd. From her friend’s location, how far ansd in what direction should Connie waldk to finally get to the store? (Ans. 1133.08 ft, 33.83o S of W)show complete solution and diagramb. Prove that, the range, R the time of flight, T and the Maximum height, H by a projectile are respectively given by; vỷ sin² e R = (5/g) sin20 , T = (2v,sin®), and H = 2g