Following are the protein contents measured in two types of species: Species 1: 0.72 1.12 0.81 0.89 0.72 0.81 1.01 0.75 0.83 Species 2: 1.21 0.93 0.80 1.12 1.22 0.94 0.87 i) Assuming normality, test the hypothesis that the two species have the same average protein contents by using 5-step hypothesis testing procedure at 5 % level of significance, and using the critical values approach. ii) Calculate the p-value of this test and make decision. iii) Write down the standard error of this test and calculate its numerical value ?

Following are the protein contents measured in two types of species: Species 1: 0.72 1.12 0.81 0.89 0.72 0.81 1.01 0.75 0.83 Species 2: 1.21 0.93 0.80 1.12 1.22 0.94 0.87 i) Assuming normality, test the hypothesis that the two species have the same average protein contents by using 5-step hypothesis testing procedure at 5 % level of significance, and using the critical values approach. ii) Calculate the p-value of this test and make decision. iii) Write down the standard error of this test and calculate its numerical value ?

Name: Following are the protein contents measured in two types of species:Sp
Uploaded: 2024-03-20T07:06:16.000Z
Channel: Bartleby
Description: Following are the protein contents measured in two types of species:Species 1: 0.72 1.12 0.81 0.89 0.72 0.81 1.01 0.75 0.83Species 2: 1.21 0.93 0.80 1.12 1.22 0.94 0.87i) Assuming normality, test the hypothesis that the two species have the sameavera

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter1: Functions

Section1.2: The Least Square Line

Problem 8E

See similar textbooks

Similar questions

A farmer has two types of beans and wants to determine which produces a better bean of greater nutritional content. A geneticist was employed to do the investigation examining genotype with nutritional content. The results were as follows: Nutritional Content Genotype High Low bb 8 4 Bb 6 2 Perform a chi square to test the association between genotype and nutritional content. State the null and alternative hypotheses and determine at 95% level of accuracy. Which hypotheses would be accepted?
The background concentration of a chemical in soil was measured on ten random specimens of soil from an uncontaminated area. The measured concentrations, in mg/kg, are: 1.4, 0.6, 1.2, 1.6, 0.5, 0.7, 0.3, 0.8, 0.2, and 0.9. Soil from a neighboring area will be declared “contaminated” if test specimens contain a chemical concentration higher than the upper 99% confidence limit of the background level. What is the cleanup target concentration?
A county environmental agency suspects that the fish in a particular polluted lake have elevated mercury levels. To confirm that suspicion, five striped basses in that lake were caught and their tissues were tested for mercury. For the purpose of comparison, four striped basses in an unpolluted lake were also caught and tested. The fish tissue mercury levels in mg/kg are given below. Sample I(From Polluted Lake) 0.523 0.723 0.523 0.623 0.523 Sample II(From Unpolluted Lake) 0.323 0.223 0.523 0.323 0.000 (a) Construct the 95% confidence interval for the difference in the population means based on these data. (b) Test, at the 5% level of significance, whether the data provide sufficient evidence to conclude that fish in the polluted lake have elevated levels of mercury in their tissue.
An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 52 43 Intermediate 55 44 Full sized 61 45 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sized H0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized H0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?Electronic H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?Electronic Find the…
Cheek teeth of extinct primates. The characteristics of cheek teeth (e.g., molars) can provide anthropologists with information on the dietary habits of extinct mammals. The cheek teeth of an extinct primate species were the subject of research reported in the American Journal of Physical Anthropology (Vol. 142, 2010). A total of 18 cheek teeth extracted from skulls discovered in western Wyoming were analyzed. Researchers recorded the dentary depth of molars (in millimeters) for a sample of 18 cheek teeth extracted from skulls. These depth measurements are listed in the accompanying table. Anthropologists know that the mean dentary depth of molars in an extinct primate species— called Species A—is 15 millimeters. Is there evidence to indicate that the sample of 18 cheek teeth come from some other extinct primate species (i.e., some species other than Species A)? The data are given below (you will need to put it into a single column). You will need to calculate the sample…
A U.S. Food Survey showed that Americans routinely eat beef in their diet. Suppose that in a study of 49 consumers in Illinois and 64 consumers in Texas the following results were obtained from two samples regarding average yearly beef consumption: Illinois Texas = 49 = 64 = 54.1lb = 60.4lb S1 = 7.0 S2 = 8.0 What is the appropriate Test statistic? Name it and Compute its value.
An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 51 42 Intermediate 55 43 Full-sized 62 47 Use ? = 0.05 to test for any significant differences. State the null and alternative hypotheses. H0: ?Computerized ≠ ?ElectronicHa: ?Computerized = ?ElectronicH0: ?Computerized = ?Electronic = ?Compact = ?Intermediate = ?Full-sizedHa: Not all the population means are equal. H0: ?Computerized = ?ElectronicHa: ?Computerized ≠ ?ElectronicH0: ?Compact ≠ ?Intermediate ≠ ?Full-sizedHa: ?Compact = ?Intermediate = ?Full-sizedH0: ?Compact = ?Intermediate = ?Full-sizedHa: ?Compact ≠ ?Intermediate ≠ ?Full-sized Find the value of…
Q.Jarjout et al conduct a study in which they measured bronchalveolar lavage (BAL) fluid histamine levels in subjects with elergic rhinitis,subject with asthama and normal volunteers .One of the measurement obtained was the total protein in BAL samples.The following are the results for the 61 samples they analysed. 76.33 57.73 74.78 100.36 73.50 77.63 88.78 77.40 51.16 62.20 149.49 86.24 57.90 72.10 67.20 54.38 54.07 91.47 62.32 44.73 55.47 95.06 71.50 73.53 57.68 51.70 114.79 61.70 47.23 78.15 53.07 106.00 35.90 85.40 72.30 61.10 72.20 41.98 59.36 63.96 66.60 69.91 59.20 54.41 59.76 128.40 67.10 83.82 95.33 88.17 109.30 79.55 58.50 82.60 153.56 84.70 62.80 70.17 44.40 61.90 55.05 Use the data to prepare; 1.A frequency distribution. 2.A relative frequency distribution. 3.A cumultative frequency distribution. 4.A box and Whisker plot.
Test the hypothesis that the average content of containers of a particular lubricant is 15 liters if the contents of a random sample of 15 containers are 10.2, 9.7, 10.1, 10.3, 10.1, 10.3, 10.1, 9.8, 9.9, 10.4, 10.3, 10.5,11.2,11.3 and 9.8 liters. Use a 0.01 level of significance and assume that the distribution of contents is normal. Also find 95% confidence interval for the population mean. Interpret your results.
Fluoride Exposure in Drinking Water Exercise 2.250 introduces a study showing that fluoride exposure might have long-term negative consequences for the offspring of pregnant women. Part of the study examines the effect of adding fluoride to tap water on mean fluoride concentration in women. Summary statistics for fluoride concentration (measured in mg/L) for the two groups are given in the table below. Tap water Fluoridated Non-fluoridated Conclusion: Sample size 141 228 Mean 0.69 0.40 St.Dev. 0.42 0.27 Find and interpret a 99% confidence interval for the mean increase in fluoride concentration for those with fluoridated tap water. Let Group 1 represent those with fluoridated tap water and Group 2 represent those without fluoridated tap water. Confidence interval: i to i (round to three decimal places)
A randc v ection of volunteers at a research institute have been exposed to a typical cold virus. After they started to have cold symptoms, 15 of them were given multivitamin tablets daily which contain 3 grams of vitamin C and various other vitamins and minerals. The remaining 15 volunteers were given placebo tablets. For each individual, the length of time taken to recover from cold is recorded. At the end of the experiment following data are obtained: Days to recover from cold Treated with multivitamin 3.0, 3.2, 6.3, 3.8, 5.8, 7.3, 5.3, 5.7, 7.9, 5.7, 6.2, 4.3, 3.8, 6.1, 4.6 Treated with placebo 7.1, 5.9, 5.5, 5.2, 2.4, 3.7, 4.9, 3.5, 4.3, 6.6, 4.5, 3.2, 3.4, 4.1, 2.9 Send data to calculator v It is known that the population standard deviation of recovery time from cold is 1.8 days when treated with multivitamin, and the population standard deviation of recovery time from cold is 1.5 days when treated with placebo tablets. It is also known that both populations are approximately…
An automobile dealer conducted a test to determine if the time in minutes needed to complete a minor engine tune-up depends on whether a computerized engine analyzer or an electronic analyzer is used. Because tune-up time varies among compact, intermediate, and full-sized cars, the three types of cars were used as blocks in the experiment. The data obtained follow. Analyzer Computerized Electronic Car Compact 49 41 Intermediate 55 44 Full-sized 64 47 Use ? = 0.05 to test for any significant differences. Find the value of the test statistic. (Round your answer to two decimal places.) Find the p-value. (Round your answer to three decimal places.) p-value =