Fluorescence confocal microscopy (FCM) - STK38 monoclonal antibody (M01), clone 2G8- 1F3. 200 μm a. What is the basic principle of image formation using this microscopy technique? b. What can be observed and concluded from the image of the specimen?
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- Calculate the scan time for a GRE with TR = 30 msec, NEX = 2, Ny = 256, for (a) a single slice and (b) 15 slices.why does a GC rich (70-80%) and GC poor (30-40%) give a low read coverage?During incubation, prepare dilutions of the standard antiserum which constitutes the standard curve for the assay (concentration in ng/mL). Add 500 µL of PBS-milk to the supplied microtube containing 500 µL of standard antiserum to obtain Standard 1 [500 ng/mL]. Identify seven microtubes for standards 2 to 7 and place 500 µL of PBS-milk in each. Calculate how much of antiserum is used in each standard ?
- A phagehunter performs a spot titer using standard techniques (3 ul of each dilution spotted to lawn) of a lysate obtained from an optimum webbed plate experiment. The phagehunter counts 4 plaques on the 10-8 dilution spot. Which of the following scenarios is the best choice for the phagehunter to do next? a.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should try to make more optimum webbed plates. b.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should adopt a phage from direct isolation. c.) The phagehunter has achieved a high enough titer lysate to move forward with characterization experiments. d.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should go back to the pick-a-plaque experiment.A phagehunter performs a spot titer using standard techniques (3 ul of each dilution spotted to lawn) of a lysate obtained from an optimum webbed plate experiment. The phagehunter counts 8 plaques on the 10-7 dilution spot. Which of the following scenarios is the best choice for the phagehunter to do next? a.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should go back to the pick-a-plaque experiment. b.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should adopt a phage from direct isolation. c.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should try to make more optimum webbed plates. d.) The phagehunter has achieved a high enough titer lysate to move forward with characterization experiments.Download BLOSUM30 and BLOSUMB0 substitu- tion matrices and place them side by side on your computer screen. What are the differences between the two matrices? Why do you see these differences?
- Fluorescence in-situ hybridisation (FISH) analysis can be performed on fixed pathological tumour sections. Briefly outline why interphase FISH is used on fixed material from a solid tumour, rather than metaphase FISHWhat is the attached enzyme in this assay and its corresponding substrate? A. Horseradish peroxidase and OPD (o-phenylenediamine dihydrochloride) B. Horseradish peroxidase and PNPP (p-Nitrophenyl Phosphate, Disodium Salt) C. Horseradish peroxidase and TMB (3,3',5,5'-tetramethylbenzidine) D. Horseradish peroxidase and ABTS (2,2'-azinobis-3-ethylbenzothiazoleine-6- sulfonic acid)Besides agarosc gel electrophoresis, there is also SDS-PAGE for separation of macromolccules. Differentiate both these methods.
- In STR typing, the homozygous condition will create a higher peak than the heterozygous condition in terms of relative fluorescence. How do the capillary electrophoresis and the electropherogram correlate?Among various dye-based assays like Biuret, Lowry, Bicinchronic Acid, and Biuret Protein Assays, what can be done if a concentrated sample is out of the detection range of chosen dye-based assay?4. Look at the gel image and answer the questions below and be specific. a) Based on your calculations of the DNA concentrations, how much DNA was loaded into each well? Do you see DNA for each of your samples? If not, why do you think that is so? b) Is the DNA in a single sharp band, multiple bands or a smear? What would each of these scenarios be due to, and why would you see them for your samples? c) Do you see multiple bands in your plasmid DNA sample? What are they?