Find the equation of the plane in xyz-space through the point P=(2,5,5) and perpendicular to the vector n=(1,−4,−5).

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.3: Lines
Problem 31E
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Find the equation of the plane in xyz-space through the point P=(2,5,5) and perpendicular to the vector n=(1,−4,−5).

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Step 1

Given:

The point on the plane is P= (2, 5, 5).

The plane is perpendicular to the vector n= (1, -4, -5)

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