Explain why the function is differentiable at the given point. f(x, y) = 9 + e-xycos(y), (π, 0) The partial derivatives aref (x, y) = (π, 0). Find the linearization L(x, y) of f(x, y) at (1, 0). L(x, y) = and fy(x, y) = ,so fx(π, 0) = and fy(π, 0) = Both fx and fy are continuous functions, so f is differentiable at

Calculus For The Life Sciences
2nd Edition
ISBN:9780321964038
Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.
Chapter9: Multivariable Calculus
Section9.CR: Chapter 9 Review
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Explain why the function is differentiable at the given point.
f(x, y) = 9 + e-xycos(y), (π, 0)
The partial derivatives aref (x, y) =
(π, 0).
Find the linearization L(x, y) of f(x, y) at (π, 0).
L(x, y) =
and fy(x, y) =
,so fx(¹, 0) =
and fy(¹, 0) =
Both fx and fy are continuous functions, so f is differentiable at
Transcribed Image Text:Explain why the function is differentiable at the given point. f(x, y) = 9 + e-xycos(y), (π, 0) The partial derivatives aref (x, y) = (π, 0). Find the linearization L(x, y) of f(x, y) at (π, 0). L(x, y) = and fy(x, y) = ,so fx(¹, 0) = and fy(¹, 0) = Both fx and fy are continuous functions, so f is differentiable at
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