Exercise 2: Carbon Containing Oxygen Molecules 1. Why is ethanol (CH₂CH₂OH) more soluble in water than 1- (CH₂CH₂CH₂CH₂CH₂CH₂OH)? hexanol 2. Why does 1-butanol (CH₂CH₂CH₂CH₂OH) have a lower boiling point than 1-hexanol (CH₂CH₂CH₂CH₂CH₂CH₂OH)?

General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter22: The Transition Elements And Coordination Compounds
Section22.4: Naming Coordination Compounds
Problem 22.1E
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Exercise 2: Carbon Containing Oxygen Molecules
1. Why is ethanol (CH₂CH₂OH) more soluble in water than 1-
(CH₂CH₂CH₂CH₂CH₂CH₂OH)?
hexanol
2. Why does 1-butanol (CH CH₂CH₂CH₂OH) have a lower
boiling point than 1-hexanol (CH₂CH₂CH₂CH₂CH₂CH₂OH)?
Transcribed Image Text:Exercise 2: Carbon Containing Oxygen Molecules 1. Why is ethanol (CH₂CH₂OH) more soluble in water than 1- (CH₂CH₂CH₂CH₂CH₂CH₂OH)? hexanol 2. Why does 1-butanol (CH CH₂CH₂CH₂OH) have a lower boiling point than 1-hexanol (CH₂CH₂CH₂CH₂CH₂CH₂OH)?
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