Example 3-8 A PMMC instrument with FSD= 100 HA and R. -1 kn is to be employed as an ac va meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current la" 0.637 100 A 0.637 157 A L- Capplied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops - 2V, (for D, and D, or D, and D) applied peak voltage - 1.414Vm total eircuit resistance - R, + R. 1414V,m- 2V, R, + R. 1.414Vm -2V, (1414 x 100 V)-(2 x0.7 V) 157 A - I ko 890.7 kn

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Chapter59: Motor Startup And Troubleshooting Basics
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And what is the used of voltmeter sensitivity in solving the value of the multiplier resistor in series with the meter resistor?

Example 3-8
A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt-
meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of
Figure 3-17. Calculate the multiplier resistance value required.
Solution
At FSD, the average current flowing through the PMMC instrument is
I.- 100 HA
100 µA
0.637
- 157 HA
peak current I.
0.637
(applied peak voltage) - (rectifier volt drop)
total circuit resistance
rectifier volt drops = 2V, (for D, and D. or Dz and D)
applied peak voltage = 1.414Vm
total circuit resistance - R, + R.
1.414Vm -2V,
R, +R.
1.414V - 2V,
--R.
(1.414 x 100 V)- (2 x 0.7 V)
157 HA
-i k0
= 890.7 kn
Transcribed Image Text:Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I.- 100 HA 100 µA 0.637 - 157 HA peak current I. 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, +R. 1.414V - 2V, --R. (1.414 x 100 V)- (2 x 0.7 V) 157 HA -i k0 = 890.7 kn
Example 3-8
A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt-
meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of
Figure 3-17. Calculate the multiplier resistance value required.
Solution
At FSD, the average current flowing through the PMMC instrument is
I- 100 HA
peak current I-
L- 100 A
0.637
- 157 HA
0.637
(applied peak voltage) - (rectifier volt drop)
total circuit resistance
rectifier volt drops = 2V, (for D, and D. or Dz and D)
applied peak voltage = 1.414Vm
total circuit resistance - R, + R.
1.414Vm -2V,
R, + R.
1.414Vm - 2V,
R,-
- R.
(1.414 x 100 V)-(2x0.7 V)
157 A
-i k0
= 890.7 kn
Transcribed Image Text:Example 3-8 A PMMC instrument with FSD = 100 LA and R=1 kn is to be employed as an ac volt- meter with FSD = 100 V (ms). Silicon diodes are used in the bridge rectifier circuit of Figure 3-17. Calculate the multiplier resistance value required. Solution At FSD, the average current flowing through the PMMC instrument is I- 100 HA peak current I- L- 100 A 0.637 - 157 HA 0.637 (applied peak voltage) - (rectifier volt drop) total circuit resistance rectifier volt drops = 2V, (for D, and D. or Dz and D) applied peak voltage = 1.414Vm total circuit resistance - R, + R. 1.414Vm -2V, R, + R. 1.414Vm - 2V, R,- - R. (1.414 x 100 V)-(2x0.7 V) 157 A -i k0 = 890.7 kn
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