Evaluate the integral: x3√36-x2dr (A) Which trig substitution is correct for this integral? Ox=36 sin(0) Ox = 36 sec (0) Ox=6 sec (0) Ox = 6 tan(0) Ox=36 tan(0) Ox = 6 sin(0) (B) Which integral do you obtain after substituting for and simplifying? Note: to enter 0, type the word theta. de (C) What is the value of the above integral in terms of 0? (D) What is the value of the original integral in terms of x? + C