Evaluate the integral , sin 60 do 3+ cos 60 using the substitution u = 3+ cos 60. sin 60 +C 3+ cos 60 = OP

Q: Evaluate the integral. 17) S sin (3x - 2) dx

A: From the given problem:   I=∫ sin3x-2dx..(1)   Let,   u=3x-2   Now differentiate with respect to x:…

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Q: evaluate the indefinite integral

A: The given integral is

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Q: Find the indefinite integral. sin' 60 cos 60 de tep 1 To solve the integral sin 60 V cos 66 de,…

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Q: Consider the integral cos x . dx where k is a positive integer. Using the methods discussed in…

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Q: Use reduction formulas to evaluate the integrals ∫ sin2 2θ cos3 2θ dθ

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Q: What substitutions are made to evaluate integrals of sin mx sin nx, sin mx cos nx, and cos mx cos…

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Q: evaluate the integral

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Q: Evaluate the integrals.∫cos 3t / (1 + sin 3t)dt

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Q: sin 40 do 9 + cos 40 Evaluate the integral ; using the substitution u = 9+ cos 40. sin 40 do 9+ cos…

A: ∫sin4θ9+cos4θ dθ

Q: Evaluate the integrals ∫cos5 x sin5 x dx

A: Given integral:

Q: Calculate the integral of 6 (cos 30) d0.

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Q: [ sin³(2x) dx

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Q: sin I dr 7+cos2 I

A: ∫sinx7+cos2xdx Put cosx=t⇒-sinx=dtdx⇒sinx dx=-dt

Q: Evaluate the integral. 6 sin" -1 dx: +C |3D NOTE: Enter the exact answer in expanded form.

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Q: Ssin( /3x)cos(-2r)dx

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Q: In evaluating sin (2x) cos(2x) dr by substitution, if u=sin(2x) then what will be the resulting…

A: The solution are next

Q: Transform the integral 7 n do d0 by the substitution r = sin o cos 0, y = sin ø sin 0 and then sin 6…

A: The formula for change of variables is given by ∬Rf(x ,y)dxdy=∬Sf[x(u,v),y(u,v)] ∂(x,y)∂(u,v) dudv…

Q: 2 sin(x) cos(5x) cos(x) dx

A: To Integrate: ∫2sin(x) cos (5x) cos(x) dx

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Q: Solve for the area common with r = 2 + 5 cos(20) and r = 5 sin(0).

A: Double integral is used to integrate the function of two variable over two-dimensional region.…

Q: Evaluate the integrals ∫sin 2θ - cos 2θ/(sin 2θ + cos 2θ)3 dθ

A: We have to evaluate the integrals: ∫sin2θ-cos2θsin2θ+cos2θ3dθ This integration will be solve d by…

Q: Evaluate the integral. [ 4 cos4 6x dx

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Q: Evaluate the integral. 6 sin x dx -1 %3D NOTE: Enter the exact answer in expanded form.

A: To evaluate the given integral.

Q: Evaluate the integral. 7- sin 6x dx 6 7n 1 7n 1 18

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Q: Evaluate the integral. 7/2 sin 8t sin 7t dt 16 O 31 O T5 3

A: the given integral is ∫0π2sin8t sin7t dt use the formula Sin C sin D= -cosC+D+cosC-D2 here C=8t and…

Q: 17 + sin w sin(1+ cos w)) dw 7-2w

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Q: Evaluate the integral. 39 sin(40) de

A: We follow the steps that are given in the solution to find the missing values.

Q: Evaluate the integral. 40 sin 80 de cos Scos cos 40 sin 80 de =

A: ∫cos74θsin8θ dθ∫cos74θ2sin4θcos4θ dθ-2-2∫cos84θ2sin4θ dθ-12∫cos84θ-2sin4θ dθ

Q: sin 70 do 2+ cos 70 Evaluate the integral , using the substitution u = 2+ cos 70. sin 70 de 2 + cos…

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Q: 3 2et + 4 sin x ) dx

A: Solve the integration

Q: Evaluate the indefinite integral! 78 cos (16x) dæ

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Q: evaluate the indefinite integral.

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Q: Evaluate the integral. ∫0 2π Sin2 (1/3θ)   dθ

A: Given: I=∫02πsin2(13θ)dθ

Q: Consider the integral /- tan(8) - In(3 cos(8)) de: This can be transformed into a basic integral by…

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Q: sin° (2æ) cos(2æ)dæ

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Q: 16. tan's cos's da

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Q: 3 tan(0) is used to evaluate an integral and the result is Suppose that the substitution x = the…

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Q: 7. Find the indefinite integral. (a) / 3 cos(") dz /32c0 31 dr

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Q: Evaluate the integrals ∫cos3 2x sin5 2x dx

A: Evaluate: ∫cos32xsin52xdx

Q: To solve the integral sin 70 V cos 70 de, rewrite the integral as 1. 2 sin 70 V cos 70 sin 70 d0.…

A: Answer is  following.

Q: Evaluate the iterated integral. * TI/4 cos(8) 3r2 sin(0) dr de

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Q: Find the indefinite integral. /. 3. sin 60 cos 60 de

A: To evaluate: I=∫sin36θcos 6θdθ =∫sin26θcos 6θ sin (6θ)dθ =∫(1-cos26θ)cos 6θ sin (6θ)dθ

Q: Evaluate the integral: 30dx / (1-cos(5x)) The solution to the integral is -6(Cot(5x) + Csc(5x)) + C…

A: Multiply by (1+cos(5x)) in numerator and denominator.

Q: To solve the integral | sin 60 Vcos 60 de, rewrite the integral as 3 sin 60 V cos 60 sin 60 de. Use…

A: The given integral is ∫sin36θ cos6θ dθ. To solve the integral ∫sin36θ cos6θ dθ, rewrite the above…