Ethyl chloride is prepared by reaction of ethylene with HCl: C₂H4(g) + HCI(g) → C₂H5C1(g) AH° = -72,3 kJ/mole What is the value of AE if 89.5 g ethylene and 125 g of HCI are allowed to react at atmospheric pressure and the volume change is -71.5 L? Answer: -223 kJ

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Ethyl chloride is prepared by reaction of ethylene with HCI:
C₂H4(g) + HCI(g) → C₂H5Cl(g) AH = -72.3 kJ/mole
What is the value of AE if 89.5 g ethylene and 125 g of HCl are allowed to react at
atmospheric pressure and the volume change is -71.5 L?
Answer: -223 kJ
Transcribed Image Text:Ethyl chloride is prepared by reaction of ethylene with HCI: C₂H4(g) + HCI(g) → C₂H5Cl(g) AH = -72.3 kJ/mole What is the value of AE if 89.5 g ethylene and 125 g of HCl are allowed to react at atmospheric pressure and the volume change is -71.5 L? Answer: -223 kJ
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