e class List; template class Node{ friend class List; private: T data; Node* link; }; template class List{ public: List(){first = 0;} void InsertBack(const T& e); void Concatenate(List& b); void Reverse();
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OOPs
In today's technology-driven world, computer programming skills are in high demand. The object-oriented programming (OOP) approach is very much useful while designing and maintaining software programs. Object-oriented programming (OOP) is a basic programming paradigm that almost every developer has used at some stage in their career.
Constructor
The easiest way to think of a constructor in object-oriented programming (OOP) languages is:
template <class T> class List;
template <class T>
class Node{
friend class List<T>;
private: T data;
Node* link;
};
template <class T>
class List{
public:
List(){first = 0;}
void InsertBack(const T& e);
void Concatenate(List<T>& b);
void Reverse();
class Iterator{
….
};
Iterator Begin();
Iterator End();
private:
Node* first;
};
I need
The question shows on below photo.
Step by step
Solved in 2 steps
- RESTRICTIONS: - Do not add any imports and do it on python .Do not use recursion. Do not use break/continue.Do not use try-except statements. def cost_to_hike_naive(m: list[list[int]], start_point: tuple[int, int],end_point: tuple[int, int]) -> int:"""Given an elevation map <m> and a start and end point, calculate the cost itwould take to hike from <start_point> to <end_point>. If the start and endpoints are the same, then return 0.Some definitions and rules:1. You can only hike to either a vertically or horizontally adjacentlocation (you cannot travel diagonally).2. You must only travel in the direction of the <end_point>. Moreexplicitly, this means that any move you make MUST take you closerto the end point, so you cannot travel in the other direction.3. We define the cost to travel between two adjacent blocks as theabsolute difference in elevation between those blocks.4. You will calculate the naive route here, so at every position, youwill have two…X New Tab rn.edgenuity.com/player/ ples Semester A « def fib(n): Complete the code for this recursive function. if n == 1: return 0 if n == 2: ZA return 1 else: x + 1 2 3 4 # The first number in the list. # The second number in the list. Ⓒ # Add the previous two numbers. fib(n-1) + fib(n - 2) v6.2.1-0055.20221212.mainline O M 31 0 DELL A 2014Computer Science (in picat) 10. split list(Lst,N): split Ist into two parts with the first part having N elements, and return a list that contains these two parts. 12. min max median(st): a function that takes a simple list of numbers Ist as a parameter and returns a list with the min, max, and the median of Ist. Can you devise an algorithm that has an expected linear running time?
- Python only* Use recursive function*. Define colorListCircles with 2 parameters Use def to define colorListCircles with 2 parameters The colorListCircles function must draw concentric circles using colors from a list. It has two parameters: the first specifies the radius of the largest circle, and the second is a list of colors. The number of concentric circles drawn is the length of the list, and these circles are colored, from largest to smallest, by the colors in the list from first to last. When viewed as nested rings, all rings should have the same thickness. If the list is empty, nothing should be drawn. We will test both how many circles are drawn as well as whether the correct circles are drawn in the correct order, you may not use any loops and you must use recursion. Also, you will still need to use drawDot. For full credit, your function should call drawDot in only one place, and should only contain one recursive call. Do not use any kind of loop Within the definition…Python only* Use recursive function*. Define colorListCircles with 2 parameters Use def to define colorListCircles with 2 parameters The colorListCircles function must draw concentric circles using colors from a list. It has two parameters: the first specifies the radius of the largest circle, and the second is a list of colors. The number of concentric circles drawn is the length of the list, and these circles are colored, from largest to smallest, by the colors in the list from first to last. When viewed as nested rings, all rings should have the same thickness. If the list is empty, nothing should be drawn. We will test both how many circles are drawn as well as whether the correct circles are drawn in the correct order, you may not use any loops and you must use recursion. Also, you will still need to use drawDot. For full credit, your function should call drawDot in only one place, and should only contain one recursive call. Do not use any kind of loop Within the definition…CodeW For fun X C Solved https://codeworkou... 臺亂 CodeWorkout X272: Recursion Programming Exercise: Is Reverse For function isReverse, write the two missing base case conditions. Given two strings, this function returns true if the two strings are identical, but are in reverse order. Otherwise it returns false. For example, if the inputs are "tac" and "cat", then the function should return true. Examples: isReverse("tac", "cat") -> true Your Answer: 1 public boolean isReverse(String s1, String s2) { 2. if > 3. 4. else if > return true; return false; 5. 6. else { String s1first = String s2last return s1first.equals (s2last) && 51. substring(0, 1); s2, substring(s2.length() 1); 7. 8. 6. isReverse(s1.substring(1), s2.substring(0, s2.length() 1)); { 12} 1:11AM 50°F Clear 12/4/2021
- 4) Recursive Analysis Homework • Unanswered The following algorithm takes an unsorted list of positive integers, along with two integers a and y. It returns the largest number, z, in the list such that either 2* = y or z9 = x is true. It returns 0 if no such z exists. The algorithm assumes that the list size, n, is a power of 2 with n > 1. 1 : integer xyMax(x, y, {a0,a1, ..., an-1}) 2 : if n == 1 3 : if (að у) or (až x) 4 return ao 5 : else 6 : return 0 7 : 8 : # process the left half 9 : 10 : m1 = xyMax(x,y,{a0,..., a4 J-1}) 11 : 12 : # process the right half 13 : m2 = xyMax(x,y,{a ;,.., an-1}) 14 : 15 : 16 : # find the largest 17 : 18 : max %3D тi 19 : if (m2 > max) 20 : 21 : 22 : max %3D тg return max 23 : end xyMax What is the recurrence relation that counts the number of comparisons for this algorithm? (The critical steps are at lines 2, 3, and 19.) What is a good big-O reference function for algorithm xyMax? (Hint: Which Master Theorem applies here?)1. Devise an algorithm that finds the sum of all the integers in a listpython: def character_gryffindor(character_list):"""Question 1You are given a list of characters in Harry Potter.Imagine you are Minerva McGonagall, and you need to pick the students from yourown house, which is Gryffindor, from the list.To do so ...- THIS MUST BE DONE IN ONE LINE- First, remove the duplicate names in the list provided- Then, remove the students that are not in Gryffindor- Finally, sort the list of students by their first name- Don't forget to return the resulting list of names!Args:character_list (list)Returns:list>>> character_gryffindor(["Scorpius Malfoy, Slytherin", "Harry Potter, Gryffindor", "Cedric Diggory, Hufflepuff", "Ronald Weasley, Gryffindor", "Luna Lovegood, Ravenclaw"])['Harry Potter, Gryffindor', 'Ronald Weasley, Gryffindor']>>> character_gryffindor(["Hermione Granger, Gryffindor", "Hermione Granger, Gryffindor", "Cedric Diggory, Hufflepuff", "Sirius Black, Gryffindor", "James Potter, Gryffindor"])['Hermione Granger, Gryffindor',…
- python: def character_gryffindor(character_list):"""Question 1You are given a list of characters in Harry Potter.Imagine you are Minerva McGonagall, and you need to pick the students from yourown house, which is Gryffindor, from the list.To do so ...- THIS MUST BE DONE IN ONE LINE- First, remove the duplicate names in the list provided- Then, remove the students that are not in Gryffindor- Finally, sort the list of students by their first name- Don't forget to return the resulting list of names!Args:character_list (list)Returns:list>>> character_gryffindor(["Scorpius Malfoy, Slytherin", "Harry Potter,Gryffindor", "Cedric Diggory, Hufflepuff", "Ronald Weasley, Gryffindor", "LunaLovegood, Ravenclaw"])['Harry Potter, Gryffindor', 'Ronald Weasley, Gryffindor']>>> character_gryffindor(["Hermione Granger, Gryffindor", "Hermione Granger,Gryffindor", "Cedric Diggory, Hufflepuff", "Sirius Black, Gryffindor", "JamesPotter, Gryffindor"])['Hermione Granger, Gryffindor', 'James…please code in python Forbidden concepts: recursion, custom classes Create a program that finds all the prime factorials of numbers from 2 to1000. Note: proof that all numbers above 1 have at least one prime factor. Add these to a list and print out the list at the end.PYTHON CODE. KEEP OUTPUT SAME. Implement the following:Given:nums = []1) Write a function appendPos() with two parameters nums and n.2) If n is positive append n to the list, nums.3) If n is not positive, do nothing.4) Call the function with the arguments, nums, and 1.5) Call the function with the arguments, nums, and 0.6) Print nums. Example Output[1]