dy vy(t) dt Submit awy²e-2at cos(wt) sin(wt) Part E w cos(wt) sin(wt) -yoe-at (a cos(wt) + w sin(wt)) Oyoe at (cos(wt) + aw cos(wt)) Ⓒ-ayo²e-2at Previous Answers ✓ Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. ▾ View Available Hint(s)

dy vy(t) dt Submit awy²e-2at cos(wt) sin(wt) Part E w cos(wt) sin(wt) -yoe-at (a cos(wt) + w sin(wt)) Oyoe at (cos(wt) + aw cos(wt)) Ⓒ-ayo²e-2at Previous Answers ✓ Correct In this example we used both the chain and product rules of differentiation to obtain an expression for the (vertical) velocity-time relationship for the car from its position-time relationship. Evaluate the numerical value of the vertical velocity of the car at time t = 0.25 s using the expression from Part D, where yo = 0.75 m, a = 0.95 1/s, and w = 6.3 rad/s. ▾ View Available Hint(s)

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 83AP: A marathon runner completes a 42.188-km course in 2 h, 30 min, and 12s. There is an uncertainty of...

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