Question 6 please $1150 (1+0.0644) 12 = 2,421.0125. What is the value of $400 at Interestrate of 5.87%0 after 10 years ofSimple annual Compounding? (use 2 decimalplace!10400+ (1+0,₁0587) ¹0 = 202.60Q6. Now work backwords. After 14 yearsaf Interest rate of 6.39%, an Investmenti's worth $1190.09, what was the initial amount.Simplede cimal places)assuming annual compaumbing? (use 2

$1150 (1+0.0644) 12 = 2,421,01 25. What is the value of $400 at interest rate of 5.87% after 10 years of Simple annual Compounding? (use 2 decimal places? |460 (1+0,0582) ¹0 = 707.60 Q6. Now work backwards. After 14 years at "interest rate of 6.39%, an Investment is worth $1190.09. what was the initial amount. assuming simple annual companding? (use 2 de cimal places)

$1150 (1+0.0644) 12 = 2,421,01 25. What is the value of $400 at interest rate of 5.87% after 10 years of Simple annual Compounding? (use 2 decimal places? |460 (1+0,0582) ¹0 = 707.60 Q6. Now work backwards. After 14 years at "interest rate of 6.39%, an Investment is worth $1190.09. what was the initial amount. assuming simple annual companding? (use 2 de cimal places)

ENGR.ECONOMIC ANALYSIS

14th Edition

ISBN:9780190931919

Author:NEWNAN

Publisher:NEWNAN

Chapter1: Making Economics Decisions

Section: Chapter Questions

Problem 1QTC

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