* Given: Maximum shear FORCE 13 KN, and moment of inertia = 120 x 10^6 mm^4. Find the maximum shear STRESS act on the .cross section shown in the figure 20 mm 250 mm 200 mm 30 mm Neutral Axis (N.A) Y=200 mm Reference Line 5 MPa 7 MPa 9 MPa 2 MPa 4 MPa 8 MPa 6 MPa 0 3 MPa 1 MPa non of them

* Given: Maximum shear FORCE 13 KN, and moment of inertia = 120 x 10^6 mm^4. Find the maximum shear STRESS act on the .cross section shown in the figure 20 mm 250 mm 200 mm 30 mm Neutral Axis (N.A) Y=200 mm Reference Line 5 MPa 7 MPa 9 MPa 2 MPa 4 MPa 8 MPa 6 MPa 0 3 MPa 1 MPa non of them

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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QUESTION 2 Question 2 A cross-section of a beam is shown in Figure Q2. If the shear force in this section is V = 125 KN, determine the value and the location of the maximum shear stress in the section. In Figure Q2, a = 30 mm and the origin of the coordinate system is at centroid of the cross section. 7 y= Z= A a AY S= 20 4a mm; mm; O Figure Q2 Answer The vertical coordinate (y-coordinate; the y-axis serves as the axis of symmetry of the cross- section.) and horizontal coordinate (z-coordinate) of the location where the maximum shear stress occurs in the section are ← a The vertical distance from the location where the maximum shear stress occurs in the section to the bottom side (AB cross section can be calculated as Distance = mm (units: mm) 3a Second moment of area The second moment of area employed in the equation to calculate maximum shear stress can be calculated as I₂ = a (units: mm²) Shear stress The second moment of area employed in the equation to calculate maximum shear…
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10 / 36 110% Q22](problem 2/28: p37) (¿ãt2) Determine the resultant `R" of the two forces Shown in fiqure, and find the angle o" between R and A- 10 800 N the x-axis . 900 N 25 4" Ane R=10379 N . 0 =66-8 Q23]( problem 2/25 's p37) Exemple201-2o At What angle x must the Type here to search
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