P2-3Determine the required magnitude of F1, F2, and F3so that the resultant couple moment is(Mc)R= [50i - 45 j - 20 k] N.m.0.2 m-F₂0.2 m-F₁0.2 mF₁F₁0.2 m-F₁-1-150 k] N0.3 m0.2 m0.3 m0.2 m-F₁-30°F₁ = [150 k] N

Moment:- Moment of any force is the measure of its tendency to rotate a body about its axis. It is…

Answered: Determine the required magnitude of F1,…

Engineering

Mechanical Engineering

Determine the required magnitude of F1, F2, and F3 so that the resultant couple moment is

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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A:01 IE 0 & F1 F2 F3 b a F4 D E B FS Consider the following values: - a - 25 m; b - 5 m; a - 25 m; d - 5 m; F1 - 3 kN; F2 - 1 kN; F3 - 4 kN; F4 - 6 kN; F5 - 8 kN; a = 30°, 0 = 60°, B= 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) - 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f)- 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 KN.m 0 353 KN.m 4] What is the resultant moment of the five forces acting on the rod about point D? b) - 184.2 kN.m )-211.9 KN.m d) 126.9 kN.m e) - 27.1 KN.m ) 125.1 kN.m a) 117.8 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting 1) 32.3 kN.m a) 11.7 KN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e) 41.1…
Q7/ Represent the resultant of the force system acting on the pipe assembly by a single force R at A and a couple M. Ans. M 100j +50h N.m 300 mm 120 N 50 N-m 250 mm 100 N A 180 N 160 N 200 mm 100A160 N 25° mm 150 mm
3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 k
F2 F3 F4 Consider the following values: - F5 a = 25 m; b = 5 n; a = 25 m; d = 5 m; F1 - 6 kN; F2 - 7 kN; F3 - 8 kN; P4 - 9 kN; PS - 10 kN; a- 45. 0-60 , - 30 1) What is the resultant moment of the five forces acting on the rod about point A? a)- S8S KNm b) 12.7AN.m 9-7.1 KNm 029AN.m ) 24.1 KN.m 0-47.1 AN.m 2) What is the resultant moment of the five forces acting on the rod about point B? a) 108 LNm 9- 191 KN.m ) 124 AN.m b) 227 AN. 4) 155 LN.am 9242 N. 3) What is the resultant moment of the five forces acting on the rod about point C? 0 35.3 KN.m )- 9.7 KN.m b) 151.I KNm 0-2088 KN.m )2179 KN.m )-1741 KN.am 4] What is the resultant moment of the five forces acting on the rod about point D? )- 217.5 AN. b) 182.7 AN )- 198.5 KN.m 4) 136.9 kN.m ) - 287.1 kN. H 310.1 ka 5] What is the moment of the force F2 about point E? a) 111.7 KN.m b) 218.1I KN.m ) 138.7 KN.m d) 193.1 KN.m e) 101.1 KN.m 0 321.3 KN.m
P2 = 60 kN P1 = 25 kN P3 = 80 kN 50° y 40° 4 m 6 m A single equivalent force R can replace the three concurrent forces acting on the beam. What is the value of e in degrees?
F1 F2 a C F3 F4 E Consider the following values: - F5 a = 1 m; b = 3 m; c = 7 m; d = 3 m; FI = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, e = 60° B= 30° 5] What is the moment of the force F2 about point E? a) 81.7 IN.m b) 78.1 KN.m c) 64.6 KN.m d) 73.1 KN.m e) 54.6 kN.m f) 61.3 KN.m
260 N.m none of the above v 13. The couple shown in the figure 10/10 (a) below is equivalent to that shown (b) if the magnitude of F and d, respectively, are * 24 N F 2 m 24 N (a) (b) 16 N and 3 m 8 N and 6 m 12 N and 4 m none of the above all of the above This form was created inside of Al-Muthanna University. Goog a Jorms A O O O O OOO O
5.) If the resultant force (single equivalent force) of the given system is known to pass through point B, what must the magnitude of the applied moment couple M be? Report a positive answer if M must be counterclockwise and a negative answer if M must be clockwise. [Answer: M = -8600 N m] 650 N 30° M -3 m 300 N -5 m- 500 N Ka -2 m- B
14. Use the same diagram for problems 14 to 19. A force F = 800 N, has its line of action in the direction from point A to point B, as shown in the figure below. Express the force F as a Cartesian vector. 2 m F- 800 N A .. 3 m 12 m •D 800 (2,9.3) (2,-9,-3) (-2,9.5) 800 A) V94 C) V94 800 B) 800 V94 (-2,9,-3) D) V94 15. Determine the components of the force F parallel to axis AD. -64 A) V94 -64 C) V94 (4,3.5) -64 B) V94 -4, 3, –5) D) 16. Determine the components of the force F perpendicular to axis AD. A) (191.43, 722.82,280.55) B) (191.43, – 722.82, –280.55) (-191.43, – 722.82, –280.55) D) (-191.43,– 722.82, 280.55) C) 17. What is the angle between OB and OD? A) 126.87° B) 127.65° C) 124.98° D) 125.84° 18. Determine the moment of the force F about point O. 800 A) M, = (12,6,-10) 800 C) M, = V94 :(-12,-6,-10) (-12,-6,10) V94 800 -10) 800 D) M, = 194 B) M, = 12,-6, 194 19. What is the moment of the force F about the axis OC? 990 A) Molloc =- (4.8.0) 960 C) Molloc = V94 890 D) Molloc = V94…
F1 F2 a F3 A B d b F4 E F5 Consider the following values: - a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 1 kN; F3 = 4 kN; F4 = 6 kN; F5 = 8 kN; a = 30°, e = 60° %3D B = 30° %3D 1] What is the resultant moment of the five forces acting on the rod about point A? a) 85.8 kN.m b) – 21.1 kN.m c) - 13.5 kN.m d) 7.9 kN.m e) 24.1 kN.m f) - 57.8 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 188.8 kN.m b) - 153.5 kN.m c) 111.6 kN.m d) - 98.9 kN.m e) 85.4 kN.m f) - 244.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 186 kN.m b) - 171 kN.m c) 155 kN.m d) 279 kN.m e) 423 kN.m f) 353 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) 117.8 kN.m b) - 184.2 kN.m c)– 211.9 kN.m d) 126.9 kN.m e) - 27.1 kN.m ) 125.1 kN.m Activate 5] What is the moment of the force F2 about point E? Go to Setting f) 32.3 kN.m a) 11.7 kN.m b) 19.8 kN.m c) 54.6 kN.m d) 9.1 kN.m e)…
F1 F2 a C F3 A d F4 D Consider the following values: - F5 a = 25 m; b = 5 m; c = 25 m; d = 5 m; F1 = 4 kN; F2 = 2 kN; F3 = 5 kN; F4 = 7 kN; F5 = 3 kN; a = 30° , 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A?
Q1: Determine the Moment of the Force 800N shown in Fig, about point O By at least 3 ways. 875 mm 625 mm 30 F = 800 N Q2: The effect or two forces FA,FB is (5 KN) and acting along u axis, determine the value of FB by parallelogram method (nun perpendicular coordinate) 00 FA-3 kN 00 00 00 #六女女六六☆☆☆会☆☆女☆☆女☆六☆☆☆☆☆女☆☆☆六☆☆☆☆女☆☆六六☆哈如セ4 位信名 8883 ******** ****** *******