Determine the number of moles of phosphorus in 7.722 g of Zn3(PO4)2. [Mr (Zn3(PO4)2) = 386.1 g mol–1] a. 2 mol b. 386.1 g mol–1 c. 4.000 × 10–2 mol d. 2.000 × 10–2 mol
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Determine the number of moles of phosphorus in 7.722 g of Zn3(PO4)2.
[Mr (Zn3(PO4)2) = 386.1 g mol–1]
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