Homework Help is Here – Start Your Trial Now!
Math
Calculus
Determine if the series Σ(-1)" 5n 1/2 + 3 converges 3n² - 3 n=1 absolutely, converges conditionally, or diverges, and justify your answer. The Series ✗(-1)" 5n / 2 +3 3n² - 3 n=1 converges by the since the absolute value of the terms Consider the absolute value of 5N 1/1 2 + 3 the series: 3n² - 3 n=1 by the to the p- series with p = which since a p-series will く if and only if n=1 5n³½ + 3 3m² - 3 and ☑ n=1 Since (−1)n 5n1/2 + 3 3n² - 3 Σ(-1)" n=1 5n 1/2 + 3 3n² - 3 > >

Determine if the series Σ(-1)" 5n 1/2 + 3 converges 3n² - 3 n=1 absolutely, converges conditionally, or diverges, and justify your answer. The Series ✗(-1)" 5n / 2 +3 3n² - 3 n=1 converges by the since the absolute value of the terms Consider the absolute value of 5N 1/1 2 + 3 the series: 3n² - 3 n=1 by the to the p- series with p = which since a p-series will く if and only if n=1 5n³½ + 3 3m² - 3 and ☑ n=1 Since (−1)n 5n1/2 + 3 3n² - 3 Σ(-1)" n=1 5n 1/2 + 3 3n² - 3 > >

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 1RE
See similar textbooks
icon
Related questions
Question
Determine if the series Σ(-1)" 5n 1/2 + 3 converges 3n² - 3 n=1 absolutely, converges conditionally, or diverges, and justify your answer. The Series ✗(-1)" 5n / 2 +3 3n² - 3 n=1 converges by the since the absolute value of the terms Consider the absolute value of 5N 1/1 2 + 3 the series: 3n² - 3 n=1 by the to the p- series with p = which since a p-series will く if and only if n=1 5n³½ + 3 3m² - 3 and ☑ n=1 Since (−1)n 5n1/2 + 3 3n² - 3 Σ(-1)" n=1 5n 1/2 + 3 3n² - 3 > >
Transcribed Image Text:Determine if the series Σ(-1)" 5n 1/2 + 3 converges 3n² - 3 n=1 absolutely, converges conditionally, or diverges, and justify your answer. The Series ✗(-1)" 5n / 2 +3 3n² - 3 n=1 converges by the since the absolute value of the terms Consider the absolute value of 5N 1/1 2 + 3 the series: 3n² - 3 n=1 by the to the p- series with p = which since a p-series will く if and only if n=1 5n³½ + 3 3m² - 3 and ☑ n=1 Since (−1)n 5n1/2 + 3 3n² - 3 Σ(-1)" n=1 5n 1/2 + 3 3n² - 3 > >
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Recommended textbooks for you
Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
Algebra
ISBN:
9781133382119
Author:
Swokowski
Publisher:
Cengage
Algebra: Structure And Method, Book 1
Algebra: Structure And Method, Book 1
Algebra
ISBN:
9780395977224
Author:
Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:
McDougal Littell
SEE MORE TEXTBOOKS