Make your solution as clear as possible, please • Derive the following equation of maximum deflection using doubleintegration method. (for type of loading see slide 7-12).M6maxat x=120EI2EIat xPb(31* - 46') at the center, if a >b48EIPPMI?WL3at Y=SEI48EI9/3 EI384EIat the center16EIwLOmax 764EIW L38max30EI192EIat x = 0.475LDeflection in Simply Supported Beams1.Px(31 – x) 8̟6EImax3EIPaPry=(3a - x) for 0 7.0,10,Pbx(1² -x²-b') for 0b48EIat the center16EI10.OXy =24EI(P - 2h² +x') }=360)ETO = 0.00652at x= 0.5191EI%3Dmax384EIô=0.00651"at the centerEI11.wLômax1 20EIATat x =wa36312.3EI L3a b=L13.Total W = wLWL3384EI14.w = N/mSmax 764EIat x = 0.475L15. WW.W 13&max192EIR,16W L3&maxR1384EI

As per bartleby guidelines, only 1st 3 parts among multiple parts questions need to be solved.…

• Derive the following equation of maximum deflection using double integration method. (for type of loading see slide 7-12). Po MI² 6max = (F-') 120EI 2EI ({1* - 48°) at the center, if a>b 48EI PP MI WL3 SEI 48EI 9/3 EI 384EI MI at the center 16EI wL dmax 764EI WL3 6max 30EI at x = 0.475L 192EI Deflection in Simply Supported Beams Px y = -(31 – x) 6EI PI max 3EI Pa 3a-x) for 0

• Derive the following equation of maximum deflection using double integration method. (for type of loading see slide 7-12). Po MI² 6max = (F-') 120EI 2EI ({1* - 48°) at the center, if a>b 48EI PP MI WL3 SEI 48EI 9/3 EI 384EI MI at the center 16EI wL dmax 764EI WL3 6max 30EI at x = 0.475L 192EI Deflection in Simply Supported Beams Px y = -(31 – x) 6EI PI max 3EI Pa 3a-x) for 0

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A Determine the maximum deflection beam shown. Use Double Integration method SOKN 90kw Lam 3 ☆ gm D
Plate 1C - Conjugate Beam Method Determine the Deflection at the internal hinge in inches unit. Use the Conjugate Beam Method. Distances are in feet. Show complete Solutions 12k 12k 16k/ft E = 29x10³ ksi I= 400 in4 hinge A В TITT C 8' 5' 5' Technology Driven by (nnovation FRU ALARANG RULMAN U TRCH [ Select ] v What is the Vertical Reaction at A? [ Select ] v What is the Moment at A? [ Select ] v What is the Vertical Reaction at B? [ Select ] v What is the slope at point B in radians??
Q1/For the 5.0m cantilever beam shown below, calculate the immediate deflection due to dead load. In addition to it is own load the beam carries a dead point load P=50kN at its end, service live load=6kN/m. Use fc-30MPa and fy-420MPa. d'=60mm, d=540mm. 500mm 300mm 3025mm 2310mm 5.00m 200mm 1,400mm | teke 60mm 60mm C
Calculate horizontal deflection at point C in the following frame using unit load method. Take EI = 92.5×10¹4 Nmm². 15 kN C D 5 kN->> 2EI 3EI B I P2K A -3 m- 2 kNm EI E 3 m2m- 1 -6 m- mm
Detormine ths reactions and moments for the beam shown using slope-deflection method. 18 k 10k E B -20 f- 10 fi- -15 f- -15 f- El = constarit
75 k 40 k Hinge 250 k-ft Determine the deflection at point D. You can use any method you prefer. B. C 12 ft 12 ft 12 ft 12 ft- 164400/EI 164600/EI 144600/EI 146400/EI
Deflection of Beams Use Virtual work Method Given: X - 274 у-74 а-8 b - 4 с- 9 Problem #1 #1 Determine the vertical displacement of joint A. Each bar is made of steel and has a cross-sectional area of 600 mm². Take E = 200 GPa. -1.5 m- -1.5 m- P = X a = A
The uniferm arcer ectangular thin plate has dimensicrs indicated and mass M- 52 kg. 2.3 T 4.5 n Decermine the mass moment of inertia in kgm- and the rsdius of gyration in meters of the thin pate about an axis through point O cirected perpendicular to the p are of the page. Peint 3 is ccsted at the upper left corner ef the pate. 'o =
2. (a). Obtain the total elongation of a steel bar of cross-sectional Area 1250mm2 acted upon by forces indicated in the diagram below. E-205,000N/mm2 15N- 5N 20N 40N 15N 1.5m 1.5m 3m Im TAt man Im 12. 5omx
PLATE # 3 CALCULATE Oo AND Yo OF THE BEAM LOADED AS SHOWN USING CONJU GATE BEAM METHOD 5KN/m 20KN 30 KN M 2m 2m 2m 2m Im 21 E CONSTANT
8 ja 10) evaluate (x+ 2)5e-(*+2) dx -2 2 16T 11) Show that xV8 – x³ dx = 9V3 0.
3. Determinethe deflection at the midspanof the continuous beam shownby using Three MomentEquation 30 KN/m A D В - 10 m 10 m -10 m E = constant E = 200 GPa I = 700 (106) mm4