Define H: R XR RxR as follows. H(x, y) = (x + 8, 9 - y) for every ordered pair (x, y) ER × R (a) Is H one-to-one? To answer this question, suppose (X1, Y₁) and (X2, y2) are in Rx R and H(X1,Y1) = H(X2 Y2). Apply the definition of H to both sides of this equation. (x + 8, 9 − y) = ( ) - Then apply the definition of ordered pair to the result. ×₁₁ + 8 = and 9 1 - = Solve these equations and apply the definition of ordered pair to obtain the result that (X₁, Y₁) ? V (×21 Y2). Therefore, H ---Select--- ✓ one-to-one. (b) Is H onto? Let (u, v) be any ordered pair in R x R. On a separate piece of paper, solve the equation (u, v) = (x + 8, 9 − y) to find values for x and y. Use the result to fill in the ordered pair below. (x, y) = (i) Is (x, y) in R x R? The numbers x and y ---Select--- real numbers because differences of real numbers ---Select--- ✓ real numbers. Hence, (x, y) ---Select--- in R x R. (ii) Does H(x, y) = (u, v)? According to the formula that defines H, we get the following in terms of u and v. H(x, y) = H + 8,9 - (u, v) (iii) Conclusion: H -Select--- onto.

Elements Of Modern Algebra
8th Edition
ISBN:9781285463230
Author:Gilbert, Linda, Jimmie
Publisher:Gilbert, Linda, Jimmie
Chapter8: Polynomials
Section8.4: Zeros Of A Polynomial
Problem 31E
Question

need help

Define H: R XR RxR as follows.
H(x, y) = (x + 8, 9 - y) for every ordered pair (x, y) ER × R
(a) Is H one-to-one?
To answer this question, suppose (X1, Y₁) and (X2, y2) are in Rx R and
H(X1,Y1)
=
H(X2 Y2).
Apply the definition of H to both sides of this equation.
(x + 8, 9 − y) = ( )
-
Then apply the definition of ordered pair to the result.
×₁₁ + 8 =
and 9 1
-
=
Solve these equations and apply the definition of ordered pair to obtain the result that (X₁, Y₁) ? V (×21 Y2).
Therefore, H ---Select--- ✓ one-to-one.
(b) Is H onto?
Let (u, v) be any ordered pair in R x R.
On a separate piece of paper, solve the equation (u, v) = (x + 8, 9 − y) to find values for x and y.
Use the result to fill in the ordered pair below.
(x, y) =
(i) Is (x, y) in R x R?
The numbers x and y ---Select---
real numbers because differences of real numbers ---Select---
✓ real numbers.
Hence, (x, y) ---Select---
in R x R.
(ii) Does H(x, y) = (u, v)?
According to the formula that defines H, we get the following in terms of u and v.
H(x, y) =
H
+ 8,9 -
(u, v)
(iii) Conclusion: H
-Select---
onto.
Transcribed Image Text:Define H: R XR RxR as follows. H(x, y) = (x + 8, 9 - y) for every ordered pair (x, y) ER × R (a) Is H one-to-one? To answer this question, suppose (X1, Y₁) and (X2, y2) are in Rx R and H(X1,Y1) = H(X2 Y2). Apply the definition of H to both sides of this equation. (x + 8, 9 − y) = ( ) - Then apply the definition of ordered pair to the result. ×₁₁ + 8 = and 9 1 - = Solve these equations and apply the definition of ordered pair to obtain the result that (X₁, Y₁) ? V (×21 Y2). Therefore, H ---Select--- ✓ one-to-one. (b) Is H onto? Let (u, v) be any ordered pair in R x R. On a separate piece of paper, solve the equation (u, v) = (x + 8, 9 − y) to find values for x and y. Use the result to fill in the ordered pair below. (x, y) = (i) Is (x, y) in R x R? The numbers x and y ---Select--- real numbers because differences of real numbers ---Select--- ✓ real numbers. Hence, (x, y) ---Select--- in R x R. (ii) Does H(x, y) = (u, v)? According to the formula that defines H, we get the following in terms of u and v. H(x, y) = H + 8,9 - (u, v) (iii) Conclusion: H -Select--- onto.
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