Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Figure σ (ksi) 0 33.2 45.5 49.4 51.5 53.4 € (in./in.) 0 0.0006 0.0010 0.0014 0.0018 0.0022 1 of 1 Part B Determine the modulus of elasticity. E = ksi Submit Part C Determine the modulus of resilience. Ur= in-lb in³ Submit Request Answer Provide Feedback Request Answer

Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Figure σ (ksi) 0 33.2 45.5 49.4 51.5 53.4 € (in./in.) 0 0.0006 0.0010 0.0014 0.0018 0.0022 1 of 1 Part B Determine the modulus of elasticity. E = ksi Submit Part C Determine the modulus of resilience. Ur= in-lb in³ Submit Request Answer Provide Feedback Request Answer

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Review Data taken from a stress-strain test for a ceramic are No elements selected o(ksi) given in the table. The curve is linear between the origin and the first point. 50 40 30 Figure 1 of 1 20 10 σ (ksi) e (in./in.) ex 10-*(in./in.) 0.5 1.0 1.5 2.0 25 33.2 0.0006 45.5 0.0010 Press (ENTER to select this element. Press (ESc to return to the main menu. Press (CTRL+Q) to quit the application. 49.4 0.0014 51.5 0.0018 53.4 0.0022
Part B Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Determine the modulus of elasticity. VO AEO vec ? E = ksi Submit Request Answer Figure 1 of 1 Part C σ (ksi) e (in./in.) Determine the modulus of resilience. ΑΣφ ? vec 33.2 0.0006 45.5 0.0010 in-lb Up = in 49.4 0.0014 51.5 0.0018 Submit Request Answer 53.4 0.0022
2) The stress-strain diagram for an alloy specimen having an original diameter of 0.5 in. and a gage length of 2 in. is shown in the figure below. TENSILE STRESS (MPA) 450 400 350 300 250 200 150 100 50 Part A 0 0 STRESS VS. STRAIN 0.002 0.004 STRAIN 0.006 Determine the modulus of resilience. Show units. Part B Determine the modulus of elasticity of the material. Part C Estimate the Yield Strength of the material. 0.008 0.01
A high-impulse universal testing machine is being used to determine the Young's Modulus of a rectangular solid specimen (l = 20 cm, t = 1.5 cm, w = 2 cm). The machine produces 35,000 Ns that causes the impact force of compression resulted to a 1 mm deformation in the length of the specimen in 0.05 s. Determine the Young's modulus of the specimen expressed in MPa. Round off your answer to the nearest whole number
7. Data taken from a stress-strain test for a ceramic are given in the table. The curve is linear between the origin and the first point. Plot the diagram, and determine the modulus of elasticity and the modulus of resilience. o (ksi) e (in. /in.) 33.2 0.0006 45.5 0.0010 49.4 0.0014 0.0018 0.0022 51.5 53.4
σ (ksi) 105 90 75 60 45 30 15 0 8 0 0 0.20 0.25 0.30 0.35 0.05 0.10 0.15 0.001 0.002 0.003 0.004 0.005 0.006 0.007 € (in./in.) The stress-strain diagram from tensile test data for a metal alloy is shown. If the diameter of testing sample is 0.5 in determine: a) UTS b) Yield Strength c) Braking/ Failure Strength d) Young Module of Elasticity e) The load causing yielding in material
In a tensile test for an aluminum alloy, the sample used is 2 inches long and 0.5 inches in diameter. The proportional portion of the tension stress-strain diagram for an aluminum alloy is shown below. _x106 lb/in² Pay attention to units and calculate your answer to 1 decimal place for the unit specified above. σ (ksi) 70 t 0.00614 Determine the modulus of elasticity for this material: € (in./in.)
30. In a typical tension test a dog-bone shaped specimen is pulled in a machine. During the test, the force F needed to pull the specimen and the length L of a gauge section are measured. This data is used for plotting a stress-strain diagram of the material. Two definitions, engineering and true, exist for stress and strain. The engineering stress F de and strain e are defined by oe F %3D and A0 L-Lo where Lo and Ao are the initial gauge 6, = Lo length and the initial cross-sectional area of the specimen, respectively. The true stress o, and strain e are defined by o, 는는 and q %3D = In A0 Lo The following are measurements of force and gauge length from a ten- sion test with an aluminum specimen. The specimen has a round cross sec- tion with a radius of 0.25 in. (before the test). The initial gauge length is 0.5 in. Use the data to calculate and generate the engineering and true stress- strain curves, both on the same plot. Label the axes and use a legend to identify the curves. Units:…
The following data was obtained as a result of tensile testing of a standard 0.505 inch diameter test specimen of magnesium. After fracture, the gage length is 2.245 inch and the diameter is 0.466 inch. a). Calculate the engineering stress and strain values to fill in the blank boxes and plot the data. Load(lb) Gage Length (in) Stress (kpsi) Strain 0 2 1000 2.00154 2000 2.00308 3000 2.00462 4000 2.00615 5000 2.00769 5500 2.014 6000 2.05 6200 (max) 2.13 6000 (fracture) 2.255 b). Calculate the modulus of elasticity c). If another identical sample of the same material is pulled only to 6000 pounds and is unloaded from there, determine the gage length of the sample after unloading.
Q1- The following data was obtained tensile test ɔn a specimen of 10 mm diameter and gauge length Lo=50 mm: 0 38 | 76.2 92.7 107 149 160.4 | 155 142 124.7 load(KN) | elongation(mm) 0 0.02 0.12 0.25 0.50 2.03 3.55 4.06 5.1 5.84 Using the graphic paper supplied, Plot engineering stress-strain curves, then determine the (ay, ey), (ou , eu), (of,, ef), modulus of elasticity, then detected in the draw ((stroin hardening (m)), (Necking), (uniform plastic region and non-uniform plastic region) and (elastic & plastic) region))?
1. A tension test on an aluminum plate resulted in the following engineering stress-engineering strain data as reported in the first and second column of the table below (reduction of area, RA=17%): S (psi) e (in/in) σ (psi) ε (in/in) 10500 0.001 10510.5 0.000995 21000 0.002 31200 0.003 41300 0.004 51200 0.005 61200 0.006 70600 0.007 74700 0.0075 76800 0.008 77600 0.0085 78000 0.009 78400 0.0095 78700 0.01 81200 0.02 83000 0.03 84200 0.04 85400 0.05 86200 0.06 86800 0.07 *87200 0.08 **86200 0.1 Note: * maximum load, ** load at fracture a) Calculate the corresponding true stress and true strain and give your results in a table along with the engineering stress, engineering strain shown in the of table above (column 3 and 4). b) Plot the true stress-true strain curve on a rectangular coordinate. c) Plot the true stress-true strain curve on a log-log graph and determine the plastic flow curve parameters K and n, the yield strength, Y, and the elastic modulus, E of the material.
640 480 160 0.002 0,004 0.006 0.008 0.010 Strain (mm/mm) A tensile test specimen of Aluminum alloy having a gauge length of 280 mm was tested to fracture. Stress and strain data obtained during the test are shown in the attached Figure. **Answers are approximate - do your best to read the graph. Determine: (a) the modulus of elasticity in GPa (4sigs). Enter this value into D2L answer box. (b) the proportional limit in MPa (3sigs). (c) the ultimate strength in MPa (3sigs). (d) Ductility of material based on percent elongation. (3sigs) Your Answer: Stress (MPa)