The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10-² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of t (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?
The following reaction is first order with respect to (CH3)3CBr and zero order with respect to CH3OH. The rate constant for the reaction is 2.28 x 10-² s¹ at 25°C. (CH3)3CBr + CH3OH (CH3)3COCH3 + HBr a. Write the rate law expression for this reaction. b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of t (CH3)3CBr to react? c. What would the concentration of (CH3)3CBr be after 20.0 minutes? d. What is the half-life for this reaction?
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter11: Chemical Kinetics: Rates Of Reactions
Section: Chapter Questions
Problem 101QRT
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![The following reaction is first order with respect to (CH3)3CBr and zero order with
respect to CH3OH. The rate constant for the reaction is 2.28 x 10² s¹ at 25°C.
(CH3)3CBr + CH3OH
(CH3)3COCH3 + HBr
a. Write the rate law expression for this reaction.
b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of the
(CH3)3CBr to react?
c. What would the concentration of (CH3)3CBr be after 20.0 minutes?
d. What is the half-life for this reaction?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F4a31084d-53de-40ac-8333-22b405fb7df5%2F5cd5aca8-72ed-42aa-9382-43c6e8eb7b16%2F9mijtyr_processed.png&w=3840&q=75)
Transcribed Image Text:The following reaction is first order with respect to (CH3)3CBr and zero order with
respect to CH3OH. The rate constant for the reaction is 2.28 x 10² s¹ at 25°C.
(CH3)3CBr + CH3OH
(CH3)3COCH3 + HBr
a. Write the rate law expression for this reaction.
b. If initial concentration of (CH3)3CBr is 0.225 M, how long does it take for 75.0% of the
(CH3)3CBr to react?
c. What would the concentration of (CH3)3CBr be after 20.0 minutes?
d. What is the half-life for this reaction?
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could you give furthur explination on how C was calculated
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