* Copyright (c) 2019 ARM Limited * SPDX-License-Identifier: Apache-2.0 */ #include "mbed.h" #define WAIT_TIME_MS 500 DigitalOut led1(LED1); int main() { printf("This is the bare metal blinky example running on Mbed OS d.d.%d.\n", MBED_MAJOR_VERSION, MBED_MINOR_VERSION, MBED_PATCH_VERSION); while (true) { led1= !led1; thread_sleep_for(WAIT_TIME_MS);
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- C CodeApproved Libraries: <stdio.h><math.h><stdlib.h><time.h> (for srand(time(0)) only)Dijkstra's algorithm Weight Class Implementationlanguage : C++ Note : Skelton Files Provided Please check the linksproject Details:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/ Files:https://ece.uwaterloo.ca/~dwharder/aads/Projects/5/Dijkstra/src/ Please provide clear and complete solution for thumps up.#include<bits/stdc++.h>#include<math.h>using namespace std; class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in…
- #include<bits/stdc++.h>#include<math.h>using namespace std; class TotalResistance{double series_res,parallel_res,sp_res;public:TotalResistance(){series_res=parallel_res=sp_res=0;}void seriesResistance(double resistance[],int n);void parallelResistance(double resistance[],int n);void spResistance(double resistance[],int n);};void TotalResistance::seriesResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];cout<<"Total Resistance in series is: "<<series_res<<endl;}void TotalResistance::parallelResistance(double resistance[],int n){double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in parallel is: "<<parallel_res<<endl;}void TotalResistance::spResistance(double resistance[],int n){for(int i=0;i<n;i++)series_res += resistance[i];double temp=0;for(int i=0;i<n;i++)temp += (1/resistance[i]);parallel_res = 1/temp;cout<<"Total Resistance in…C++ Code /////// #include <iostream> class BTNode {public:int item;BTNode *left;BTNode *right;BTNode(int i, BTNode *l=nullptr, BTNode *r=nullptr):item(i),left(l),right(r){}}; BTNode *root = nullptr; void insert(int i) {//implement code here} int main(){insert (5);insert (10);insert (1);if (root){std::cout << "root = " << root->item << std::endl;if (root->left)std::cout << "root->left = " << root->left->item << std::endl;if (root->right)std::cout << "root->right = " << root->right->item << std::endl;}return 0;}#include void main(void) { int c =2 ^3; cout<< c; }
- PROGRAMMING LANGUAGE: C++ // vectors: overloading operators example#include <iostream>using namespace std;class counter{private:int count;public:counter():count(0){}counter(int c):count(c) {} int get_count(){return count;} counter operator++ (int){return counter(count++); } counter operator-- (int){return counter(count--);}};int main(){counter c1, c2, c3;c1++;c2--;cout<<'\n'<<c1.get_count();cout<<'\n'<<c2.get_count();cout<<endl;c3 = c1++;cout<<'\n'<<c1.get_count();cout<<'\n'<<c3.get_count();getch();return 0;} Go through the above code and write the output of the given code segment. counter c1(5), c2(10), c3;c3=c1++;c2=--c3;;cout<<”\n”<<c1.get_count();cout<<”\n”<<c2.get_count();cout<<”\n”<<c3.get_count();C programming pseudocode pointers help. { totalInAGivenHour+=*(rawReadings+ monthNo*30*14*4 + 14*4*nThDateOfMonth+ 4*nThHourOfDateFrom7AM + nThReadingTimeOfHour); // the pointer is to assign the values in the bracket and storing them in totalInAGivenHour }Computer Science A tool is attached to link 3 of the manipulator. This tool is described by TTW, the tool frame relative to the wrist frame. Also, a user has described his work area, the station frame relative to the base of the robot, as TSB. Write the subroutine Procedure SOLVE(VAR trels: frame; VAR current, near, far: vec3; VAR sol: boolean); where “trels” is the {T} frame specified relative to the {S} frame. Other parameters are exactly as in the INVKIN subroutine. The definitions of {T} and {S} should be globally defined variables or constants. SOLVE should use calls to TMULT, TINVERT, and INVKIN
- EXPLAIN LINE BY LINE THIS ARDUINO CODE Please explain each and every line in detail Simple Cylon Cylon Eye sweep using 5 LEDs */ unsigned char upDown=1; unsigned char cylon=0; void setup() { DDRB = B00011111; } void loop() { if(upDown==1){ cylon++; if(cylon>=4) upDown=0; } else { cylon--; if(cylon==0) upDown=1; } PORTB = 1 << cylon; delay(150); }JAVA LANGUAGE CODE Postfix Calculator by CodeChum Admin One good implementation of computing infix expressions is to transform them to postfix and then evaluate via the postfix expression. Infix expressions is the common way of writing arithmetic expressions. The binary operator come between them as shown below: 2 * 5 + 9 - 10 / 20 In postfix expressions, the operands come first before the operator: 2 5 * 9 + 10 20 / - A stack can be used to evaluate postfix expressions. The operands are pushed onto the Stack and when an operator is found two operands are popped and the operation is performed and finally the result is pushed back onto the Stack. The final answer will be the lone element of the Stack. Input The first line contains a positive integer n representing the number of postfix expressions. What follows are n postfix expressions themselves. 5 10 20 + 30 15 2 * + 100 20 30 + / 90 20 10 + + 0 / 9 3 - 10 + 2 * Output A single line containing the result of…Part-2--- objective: Modify the assembly function-asm_led - so it will flip an integer between -e- and - 1. Use the result to blink an- LED. Also describe why we are-using the static qualifier here void part2() { //-what does this qualifier do? static uint8_t ledVar = 0; ledVar = asm_led(ledVar); led1 = ledVar; Embedded Systems, This is for ARM Assembler. Please find a Assembly code that will change ledVar to 0 and 1 to blink an LED