\ Convert the following infix expression into postfix one: (A+B^D)/(D-F)+G PS: you have to illustrate the different steps of this conversion one by one.
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Q1 \ Convert the following infix expression into postfix one:
(A+B^D)/(D-F)+G
PS: you have to illustrate the different steps of this conversion one by one.
Step by step
Solved in 2 steps with 1 images
- The Deque ADT combines characteristics of the Stack and the Queue. The name “Deque" comes from "double-ended queue" and is usually pronounced "deck". Like the Stack and the Queue, a Deque permits elements to be accessed only at the ends. However, a Deque allows items to be added at either end and removed from either end. We can refer to the operations supported by the Deque as enqueueFront, enqueueRear, dequeueFront, and dequeueRear. Note that once you have a Deque, you can use it to implement both the Stack and the Queue. Implement the Deque using a dynamic, linked implementation (15pts) Use your Deque to implement a Stack (15pts). Use your Deque to implement a Queue (15pts). Test your implementation across the 3 data structures to tell the story of your work (10pts).void pop()// Pre: size() > 0.// Post: The highest priority item has been removed from the// p_queue. (If several items have the equal priority,// then the implementation may decide which one to remove.)// void p_queue::pop() { cerr << "pop() not implemented yet" << endl; }3- Write a program that randomly generates 10 numbers (between 1 and 8), inserts into queue and then finds how many distinct elements exist in the queue. Example 1: Example 2: Queue: 2 40 3 3 2 18 4 18 18 3 Queue: 1 1 4 33 16 16 4 16 4 Output: 5 Output: 4 Notes: • You must use ONLY queue data structure. Don't use other different data structures like string or normal (pure) array or stack or array list. • Don't write any other method in the Qeueu class. All methods must be written in the main program.
- Q/ In java language Create a Queue (capacity of 10 Students) of 6 different students according to their ID number De-queue one students and En-queue two Students by displaying their Front and Rear Values.ListQueue Node Node Node front= next next= next = nul1 rear = data "Thome" data "Abreu" data - "Jones" size - 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 4. How do you push a node with data, "Chu" to the above queue? front.next = new Node("Chu", front); a. b. front = new Node ("Chu", front) rear = new Node("Chu", rear) с. d. = new Node ("Chu", rear.next) rear Describe the reason of your choice. Your answer is (a, b, c, or d) Will the push action take time in 0(1) or 0(n)? Next Page Type here to searchIf a queue is empty, Select one: A.You can dequeue an element from the queue B.The size of the queue is 1 C.You cannot enqueue an element into the queue. D.You cannot dequeue an element from the queue.
- Computer Science A string represents a sequence of operations to be performed when implementing the Queue ADT. Theletter means the "put" operation, the asterisk means the "get" operation. What will remain in the queueafter performing the above operations? DB**KK*R**Q7. Which values will be contained in the queue and the stack after the two while loops? Queue queue = new Queue (10); Stack stack = new Stack(25); for (int i = 1; iInput : 1->2->3->2->1->NULL Output: It's a palindrome !!! Create a palindrome of your student ID and then push the element to the stack and queue. Pop each element from the stack and the queue and then check for the mismatch.
- Queue abcQ = new Queue (); Queue out = new Queue (); //statements to insert value 1, 2, 3, 4, 5 into abcQ for (int i = 0; i < 5; i++) { int a = Integer.parseInt (abcQ.dequeue ().tostring ()); int b = Integer.parseInt (abcQ.dequeue ().tostring ()); abcQ.enqueue (a); abcQ.enqueue (b); out.enqueue (a + b); for (int i = 0; i < 5; i++) System.out.print (abcQ.dequeue () + " "); System.out.println ("\n") ; for (int i = 0; i < 5; i++) System.out.print (out.dequeue () + " "); (- ks)ListQueue Node Node Node front- next = next next - nul1 data - "Jones" rear data "Thome" data - "Abreu" size = 3 The above is a queue of a waiting list. The ListQueue has a node (front) to record the address of the front element of a queue. It also has another node (rear) to record the address of the tail element of a queue. 3. How do you pop a node from the above queue? a. front.next = front; b. front = front.next с. rear = rear.next d. rear.next = rear Describe the reason of your choice. Your answer is (a, b, c or d) will the pop action take time in 0(1) or 0(n)? Next Page P Type here to searchRadix Sorting Algorithm In C++, implement the radix sorting algorithm using a queue class.Steps: Create a queue filled with 10 random integers between 1000 and 9999. Next, create a list of 10 empty queues (0-9 digit bins), then dequeue each number from the main queue and enqueue them into the correct digit bin. Dequeue the numbers from each digit bin in order and enqueue them back into the main queue. Repeat the process for every digit (tens, hundreds, thousands, etc.) Finally, print the sorted list.