Construct a cash flow diagram that represents the amount of money that will be accumulated in 15 years from an investment of $40,000 now at an interest rate of 8% per year.
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- Identify the engineering economy symbols and their values. Use a question mark with the symbol whose value is to be determined. Fifteen years ago your grandfather invested $18,000 in a stock fund to pay for your college education. Each year thereafter, he deposited $2,600 into the fund. If the investments grew at a rate of 8% per year over the 15 years, how much is in the fund now? $18,000 = (Click to select) n A i F P $2,600 = (Click to select) F i A n P 0.08 = (Click to select) P n i A F 15 = (Click to select) n P i A F ? = (Click to select) P n i A FEngineering Economics 00013 Please provide a step by step solution using Rate of Return (ROR) ThankyouChoose the formula that you will use for the following case: A major repair on the suspension system of a 5-year-old car cost $2000. The cost of periodic maintenance has been $800 every 2 years. If the owner donates the car to charity after 8 years of ownership, what is the quivalent annual cost of the repair and maintenance in the 8-year period of ownership? Use an interest rate of 8% per year, and assume that the owner paid the $800 maintenance cost immediately before donating the car in year 8. AW = -2000 (A/P, 8%, 8) - 800 (A/P, 8%, 2) - 800 (A/P,8%, 4) - 800 (A/P, 8%, 6) - 800 (A/P,8%, 8) PW = -2000 (P/A, 8%, 8) - 800 (P/A, 8%, 2) - 800 (PIA, 8%, 4) - 800 (P/A, 8%, 6) - 800 (P/A, 8%, 8) PW = -2000 (P/F, 8%, 8) - 800 (P/F, 8%, 2) - 800 (P/F, 8%, 4) - 800 (P/F, 8%, 6) - 800 (P/F, 8%, 8) AW = -2000 (A/F, 8%, 8) - 800 (A/F, 8%, 2) - 800 (A/F,8%, 4) - 800 (A/F, 8%, 6) - 800 (A/F,8%, 8)
- Parkhill, Smith, and Cooper, a consulting engineering firm, pays a bonus to each engineer at the end of the year based on the company’s profit for that year. If the company’s initial investment was $1.2 million, what rate of return has it made if each engineer’s bonus has been $3000 per year for the past 10 years? Assume the company has six engineers and that the bonus money represents 5% of the company’s profit.Constructacashflowdiagramforthefollowing:$10,000outflowattime zero, $3000 per year inflow in years 1 through 5 at an interest rate of 10% per year, and an unknown future amount in year 5State the purpose for each of the following built-in spreadsheet functions:a. FV(i%,n,A,P)b. IRR(first_cell:last_cell)c. PMT(i%,n,P,F)d. PV(i%,n,A,F)
- Construct a cash flow diagram for the following cash flows: $25,000 outflow at time 0, $9000 per year inflow in years 1 through 5 at an interest rate of 10% per year, and an unknown future amount in year 5.Callahan Construction borrowed $2.6 million to finance the construction of an entertainment complex in a smart community development project. The company made “interest only” payments of $312,000 each year for 3 years and then repaid the principal in a single lump sum payment of $2.6 million. What was the interest rate on the loan?Construct a cash flow diagram that represents the amount of money that will be accumulated in 7 years from an initial investment of $24,000 now and $3,000 per year for 7 years at an interest rate of 12% per year. I hope someone can help me and explain how it is solved
- ENGINEERING ECONOMICS For a company that uses a year as its interest period,determine the net cash fl ow that will be recorded at the end of the year from the cash flows shown.Company B expects to invest $935,000 for one heavy equipment replacement 2 years from now and another $1.1 million 4 years from now. How much the company deposit into a sinking fund each month to provide for the purchases, if the fund earns a rate of return of 12% per year compounded monthly? Use excel spreadsheet with excel functions. If you aren't going to show the excel functions don't even answer..(a) Calculate the amount deposited 1 year ago to have $1000 now at an interest rate of 5% per year. • (b) Calculate the amount of interest earned during this time period. please show me how you solved it mathematically