Consider the following regression estimates Source SS df Model 44.5315181 Residual 103.798233 Total 148.329751 MS 2 22.2657591 523 . 198466985 525 .28253286 Number of obs F(2, 523) Prob > F R-squared Adj R-squared Root MSE = = = II = II = 526 112.19 0.0000 0.3002 0.2975 .4455
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- Use the following ANOVA table for regression to answer the questions. Response: Y Source DF Sum Sq Mean Sq F-value Pr(>F) Regression 1 347.95 347.95 13.27 0.000 Residual Error 359 9412.98 26.22 Total 360 9760.93 Give the F-statistic and p-value. Use the following ANOVA table for regression to answer the questions. Response: Y Source DF Sum Sq Mean Sq F-value Pr(>F) Regression 1 10.756 10.756 2.89 0.090 Residual Error 342 1272.924 3.722 Total 343 1283.680 Give the F-statistic and p-value.Find the z-score that has 30.5% of the distribution's area to its left. The z-score is |. (Round to two decimal places as needed.)Pyramid Lake is on the Palute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a tells you that the average length of trout caught in Pyramid Lake Is mu = 19 Inches. Howevera survey reported that of a random sample of 46 fish caught, the mean length was overline x =18.6 lnch , with estimated standard s = 2.7 inches. these data Indicate that the average length of a trout caught in Pyramid Lake less than mu = 19 inches? Use a=0.05 Please answer ONLY parts D & E
- Pyramid Lake is on the Palute Indian Reservation in Nevada. The lake is famous for cutthroat trout. Suppose a tells you that the average length of trout caught in Pyramid Lake Is mu = 19 Inches. Howevera survey reported that of a random sample of 46 fish caught, the mean length was overline x =18.6 lnch , with estimated standard s = 2.7 inches. these data Indicate that the average length of a trout caught in Pyramid Lake less than mu = 19 inches? Use a=0.05 Please answer parts A,B, & Cfind the z-score that has 30.5% of the distributions area to its left.x = 7203.191, s = 543.5400, n = 30. After normal probability plot diagnostic, normality assumption is validated. Construct a Cl of 95% level for μ.
- Use the following ANOVA table for regression to answer the questions. Response: Y Source DF Sum Sq Mean Sq F-value Pr(>F) Regression 1 10.351 10.351 2.89 0.090 Residual Error 342 1225.044 3.582 Total 343 1235.395 Give the F-statistic and p-value.Enter the exact answers.The F-statistic is .The p-value is .Analyse the following regression Regression Statistics Multiple R 0.79716916 R Square 0.63547867 Adjusted R Square 0.63254686 Standard Error 198.375358 Observations 377 ANOVA df SS MS F Significance F Regression 3 25589530 8529843.34 216.753245 2.2501E-81 Residual 373 14678587.9 39352.7826 Total 376 40268117.9 Coefficients Standard Error t Stat P-value Lower 95% Upper 95% Lower 95.0% Upper 95.0% Intercept -97.981174 79.2847437 -1.2358137 0.21730553 -253.88228 57.9199296 -253.88228 57.9199296 EquivArea 3.5523258 0.15149067 23.4491399 2.2549E-75 3.254443 3.85020861 3.254443 3.85020861 Years 2.04629486 0.31770115 6.44094253 3.6636E-10 1.42158501 2.67100471 1.42158501 2.67100471 Condition 15.0379067 10.2144479 1.47221924 0.14180492 -5.0472147 35.1230282 -5.0472147 35.1230282A regression analysis done with Excel for the relationship between The placement test scores and the final grades for 20 students who took the regular course were recorded and yielded the following output. SUMMARY OUTPUT Regression Storistics Multiple R 0.45351 R Square 0.20567 Adjusted F 0.16155 Standard E 16.1747 Observatic 20 ANOVA MS F SS 4.66073 1219.35 gnificance F 0.04461 1 1219.35 Regressior Residual Total 18 4709.2 261.622 19 5928.55 Chart Area Coefficientsandard Errt Stat P-value Lower 95% Upper 95%ower 95.0%pper 95.0% 0.0192 5.95316 59.0587 5.95316 59.0587 Intercept 32.5059 12.6386 2.57195 X Variable 0.47106 0.2182 2.15887 0.04461 0.01264 0.92948 0.01264 0.92948 According to the model, If the placement test score is 79, the course grade will be A. 32.51 B. 69.64 C. 32.95 D. 91
- Use the following ANOVA table for regression to answer the questions. Response: Y Source DF Sum Sq Mean Sq F-value Pr(>F) Regression 1 343.82 343.82 13.80 0.000 Residual Error 359 8942.69 24.91 Total 360 9286.51 Give the F-statistic and p-value.Enter the exact answers.The F-statistic is Enter your answer; F-statistic .The p-value is Enter your answer; p-valueDO NOT USE MICROSPFT EXCEL. Show the step-by-step solution and create a NORMAL CURVE for the problem.A special bumper was installed on selected vehicles in a large fleet. The dollar cost of body repairs was recorded for all vehicles that were involved in accidents over a 1-year period. Those with the special bumper are the test group and the other vehicles are the control group, shown below. Each "repair incident" is defined as an invoice (which might include more than one separate type of damage). Statistic Test Group Control Group Mean Damage x¯1x¯1 = $ 1,101 x¯2x¯2 = $ 1,766 Sample Standard Deviation s1 = $ 696 s2 = $ 838 Repair Incidents n1 = 12 n2 = 9 (a) Construct a 90 percent confidence interval for the true difference of the means assuming equal variances. (Round answers to 3 decimal places. Negative values should be indicated by a minus sign.) (b) Repeat part (a), using the assumption of unequal variances with Welch's formula for d.f. (Round answers to 2 decimal places. Negative values should be indicated by a minus sign.) (d) Construct separate…