Consider the following hash table, and a hash function of key % 5. What would bucket 3's list be after the following operations?hashTable:+ 25955012368 + 33 + 4884 54HashRemove(hashTable, 25)HashRemove(hashTable, 48)Hashlnsert(hashTable, item 53)О а. 33, 53O b.68, 33, 53О с. 68, 33, 48O d. 68, 33, 48, 53

Hashing is generally used as a hash function that converts a given number or any other key to a…

Consider the following hash table, and a hash function of key % 5. What would bucket 3's list be after the following operations? hashTable: 25 95 50 1 2 3 68 33 48 4 84 54 HashRemove(hashTable, 25) HashRemove(hashTable, 48) Hashlnsert(hash Table, item 53) О а. 33, 53 O b.68, 33, 53 О с. 68, 33, 48 O d. 68, 33, 48, 53

Consider the following hash table, and a hash function of key % 5. What would bucket 3's list be after the following operations? hashTable: 25 95 50 1 2 3 68 33 48 4 84 54 HashRemove(hashTable, 25) HashRemove(hashTable, 48) Hashlnsert(hash Table, item 53) О а. 33, 53 O b.68, 33, 53 О с. 68, 33, 48 O d. 68, 33, 48, 53

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The hash function h(k)= [(m(kA mod 1)] for A = 2-³ is used to insert the keys 61, 62, 63, 64, and 65 into a hash table of size m = 1000. The order of the hash codes in the table are given by a. 625, 125, 0, 750, 875 b. 625, 750, 625, 125, 0 c. 625,125, 0, 875, 750 d. 625, 750, 875, 0, 125 e. 625, 750, 125, 875, 0
Assume a hash table utilizes an array of 13 elements and that collisions are handled by separate chaining. Considering the hash function is defined as: h(k)=k mod 13. i) Draw the contents of the table after inserting elements with the following keys: 36, 243, 261, 180, 217, 180, 21, 16, 182, 202, 91, 97, 166, 78, 33, 70, 51, 58.
The hash table array has capacity of 10. Capacity is the number of slots present in the array that is used to build the hashtable. The hash function returns the absolute value of the key mod the capacity of the hash table. a) Insert these keys in the hash table: 3,23,11,21,1,7,77,8 where the hash table uses quadratic probing to resolve collisions. b) Search and Delete 3 and 11 from the table. Be careful about changing the status of the table slot to “deleted” after deleting each item. c)Search 23 and 21 from the table and print their position.
3. Given the following keys: 68, 39, 89, 28, 79 Take alpha = 0.6 Compute m (size of hash table), and select it to be a prime number. Now illustrate how you would construct the hash table. Use double hashing as collision resolving technique. The original hash function, is h(k)= k mod m The second hash function for double hashing, h₂(k)=8-(k mod 8)
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